I need to pass command arguments with a batch file. How would I do that? I have a little program set up but I don't know how to get the command arguments.. or really how to make a command.
@echo OFF
title Name pl0x
color 0a
:start
set INPUT=
set /P INPUT= %=%
IF "%INPUT%"=="/mynameis" (
goto :init
) ELSE (
goto :start
)
:init
Pause&Exit
REM Here, I'd print the name, like this: echo.Hello, %name%
REM I just don't have the variable. And I don't know how to set it.
Arguments are done with %1 %2, etc
So if you have mynameis.bat %1 will contain test
An argument is a delimited word by a space wich you can use like a parameter in a application.
Then if call a script like this:
Script.Bat word1 word2 word3_word4-word5
The arguments are:
Argument 1 = "word1"
Argument 2 = "word2"
Argument 3 = "word3_word4-word5" (Because any space).
In Batch arguments are stored in special vars from %1 to %255 where %1 equals to the "Argument 1".
%0 equals to the current script name or procedure name.
%* joins all th arguments
..And the special modifier ~ expand the argument without double quotes.
Then if we have this code:
@Echo OFF
If /I "%~1" EQU "/Print" (Echo: You called the function "%~1" with the value: "%~2"))
We are checking if argument 1 is equals to "/Print", then if is equals prints the value for the switch, the second argument.
Then you can call your bat like this:
Script.bat /Print Hello!
Learn more about Batch arguments here: http://ss64.com/nt/syntax-args.html
