why does a stack program segment have executable attribute

Question

Here is a dump from a.out

STACK off 0x00000000 vaddr 0x00000000 paddr 0x00000000 align 2**2 filesz 0x00000000 memsz 0x00000000 flags rwx

Why does a stack segment have executable attribute?

Why isn't there a heap segment with rw- attribute?

//On ubuntu 32bit machine. Program is a simple hello world.

Command: ld test.o startup.s; objdump -dhSxt -M intel-pneumonic a.out //startup.s has a small assembly code with _start symbol which calls main and exits after main returns.

You'll need to give your compiler flags and the command you're running. — teppic
– teppic, Commented Mar 31, 2013 at 15:18
The stack is allowed to be executable, but I'm surprised it's a default. On my copy of Ubuntu it isn't. — teppic
– teppic, Commented Mar 31, 2013 at 17:39
@teppic, I apologize. the actual command I used was ld test.o startup.s, where I had assembly code with _startup symbol. There is some context here - airs.com/blog/archives/518 — Chethan
– Chethan, Commented Apr 1, 2013 at 4:56

Employed Russian · Accepted Answer · 2013-03-31 16:54:17Z

1

Command: gcc test.c

Try gcc test.c -Wl,-z,noexecstack.

That should be the default on any reasonably modern distribution.

answered Mar 31, 2013 at 16:54

Employed Russian

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