14 
def applejuice(q):
   print THE FUNCTION NAME!

It should result in "applejuice" as a string.

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4
  • 1
    See meta.stackexchange.com/questions/18584/… Commented Oct 8, 2009 at 20:39
  • 1
    From the answer you chose we can conclude that this was indeed a duplicate. Indeed, a question almost exactly the same name already existed: stackoverflow.com/questions/251464/… Commented Oct 8, 2009 at 21:45
  • I disagree that this is a duplicate of #251464 -- it seems like this question is the inverse instead. Commented Nov 10, 2012 at 19:09
  • What should it print in this case : def applejuice(): print "thefunctionname"; orangejuice = applejuice; del applejuice; orangejuice(); Commented Feb 25, 2015 at 11:52

7 Answers 7

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22

This also works:

import sys

def applejuice(q):
    func_name = sys._getframe().f_code.co_name
    print func_name
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11 
def applejuice(**args):
    print "Running the function 'applejuice'"
    pass

or use:

myfunc.__name__

>>> print applejuice.__name__
'applejuice'

Also, see how-to-get-the-function-name-as-string-in-python

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1 Comment

this isn't from inside the function
8 
import traceback

def applejuice(q):
   stack = traceback.extract_stack()
   (filename, line, procname, text) = stack[-1]
   print procname

I assume this is used for debugging, so you might want to look into the other procedures offered by the traceback module. They'll let you print the entire call stack, exception traces, etc.

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3

Another way

import inspect 
def applejuice(q):
    print inspect.getframeinfo(inspect.currentframe())[2]
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2

You need to explain what your problem is. Because the answer to your question is:

print "applejuice"
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2 Comments

maybe he means: def func(anothah_func): print anothah_func's name
Well, that's definitely possible. We'll see if he says what the problem is.
1

This site gave me a decent explanation of how sys._getframe.f_code.co_name works that returns the function name.

http://code.activestate.com/recipes/66062-determining-current-function-name/

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1 Comment

Wlecome to SO! please, think about providing explanation, and not only pointing to external links.
0 
def foo():
    # a func can just make a call to itself and fetch the name
    funcName = foo.__name__
    # print it
    print 'Internal: {0}'.format(funcName)
    # return it
    return funcName

# you can fetch the name externally
fooName = foo.__name__
print 'The name of {0} as fetched: {0}'.format(fooName)

# print what name foo returned in this example
whatIsTheName = foo()
print 'The name foo returned is: {0}'.format(whatIsTheName)
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