Json dynamic string list

Question

I want to return a list of validation errors from my mvc app to the client side to I can take use of the jquery validation showErrors which takes an object

I can get a list of fields and the the erorr(s) that apply to them in any way that is best suited.

I have tried a few formats already, dictionary and none of these serialise to the correct structure as required by the validation library.

ie.

{"fieldname":"some error for fieldname", "fieldname2": "some error for fieldname2"}

All of my examples seem to serialise into something along the lines of

{"Key": "fieldname", "Value" : "some error for fieldname"}

What is the best way to return my data and how can I get it serialised in the correct way that I need?

Daniel Powell · Accepted Answer · 2012-11-26 22:19:01Z

1

I suggest you use Json.NET (it is default JSON serializer for ASP.NET MVC 4 as well) and its JsonWriter:

StringWriter errorsStringWriter = new StringWriter();
JsonWriter errorsJsonWriter = new JsonWriter(jsonStringWriter);
errorsJsonWriter.WriteStartObject();
errorsJsonWriter.WritePropertyName("fieldname"); 
errorsJsonWriter.WriteValue("some error for fieldname");
errorsJsonWriter.WritePropertyName("fieldname2"); 
errorsJsonWriter.WriteValue("some error for fieldname2");
...
errorsJsonWriter.WriteEndObject();
errorsJsonWriter.Flush();

You can return JSON generated this way with ContentResult:

return Content(errorsStringWriter.GetStringBuilder().ToString(), "application/json");

UPDATE

Json.NET also supports dynamic JSON through JObject. In that case your code can look like this:

var jsonObject = new JObject();
jsonObject.Add("fieldname", "some error for fieldname");
jsonObject.Add("fieldname2", "some error for fieldname2");
...

Creating ContentResult in this case can look like this:

    return Content(jsonObject.ToString(Newtonsoft.Json.Formatting.None), "application/json");

edited Nov 26, 2012 at 22:19

Daniel Powell

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answered Nov 22, 2012 at 12:27

tpeczek

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8 Comments

Daniel Powell Over a year ago

this looks very promising will have to try it out

Daniel Powell Over a year ago

hmm using the json object just returns [[]]

tpeczek Over a year ago

@DanielPowell You mean the return Json(jsonObject); approach?

Daniel Powell Over a year ago

yeah, see stackoverflow.com/questions/13562734/…

tpeczek Over a year ago

@DanielPowell I can't retest it until later today, at this point I can only suggest catsing to dynamic before adding objects to JArray: jsonArray.Add(json as dynamic);. Please check that and let me know if this helps.

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