Possible Duplicate:
How do I get the application exit code from a Windows command line?
The Perl script that I'm calling inside batch returns a 1, 2, or 3. What's the syntax for calling this perl sript with an argument 829, and capturing the script's exit code?
Perl.exe listMembership.pl 829 in cmd.exe
@echo off
set retVal=Perl.exe listMembership.pl 829
echo %retVal%
Take a look at the output of if /? on the command line. Without cmd extensions, the lowest common denominator batch script would be something along the lines of:
@echo off
Perl.exe listMembership.pl 829
if errorlevel 4 goto error
if errorlevel 3 goto exit3
if errorlevel 2 goto exit2
if errorlevel 1 goto exit1
if errorlevel 0 goto exit0
:error
echo:Unexpected exit code %ERRORLEVEL%
goto end
:exit3
echo:Forbnicate
goto end
:exit2
echo:Colormaticate
goto end
:exit1
echo:Motorcade
goto end
:exit0
echo:Is this really success?
goto end
:end
echo:Done
Keep in mind, errorlevel checks have to be in descending order because:
ERRORLEVEL number Specifies a true condition if the last program run
returned an exit code equal to or greater than the number
specified.
