Checking strings with

Question

I have a series of if statements in a function like this:

if time == "%%00":
    #code
elif time == "%%15":
    #code
elif time == "%%30":
    #code
elif time == "%%45":
    #code

Where time is 24 hour format ie. 0000-2400 and I'm checking what 15 interval time is at. All the statements are ignored however, so "%%interval" doesn't work. Is it just something simple I'm missing here or do I need a different method?

What in the world would make you think % is some kind of crazy string wildcard in Python (or that equality tests accept wildcards to begin with)? — kindall
– kindall, Commented Jun 20, 2012 at 5:50
I've been doing my first semester of sql at the same time and it uses % in statements such as WHERE str LIKE "%asd%". I thought it'd work similarly in python. — Markaj
– Markaj, Commented Jun 20, 2012 at 5:54

Sufian Latif · Accepted Answer · 2013-12-25 09:39:30Z

7

There are several ways to do it:

if time.endswith("00"):
    #code
elif time[-2:] == "15":
    #code
elif re.match(".{2}30", time):
    #code
elif time.endswith("45"):
    #code

edited Dec 25, 2013 at 9:39

answered Jun 20, 2012 at 5:46

Sufian Latif

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Comments

Samy Vilar · Accepted Answer · 2012-06-20 05:59:31Z

fundamentally you are comparing string literals and nothing more, theres a couple ways of doing this, heres one without regular expressions.

if   time[-2:] == "00":
    #code
elif time[-2:] == "15":
    #code
elif time[-2:] == "30":
    #code
elif time[-2:] == "45":
    #code

[-2:] will grab the last two chars from the string

heres one with regular expression, Im not a big fan of them, they can generate subtle bugs, but thats just my opinion.

if re.match('..00', time):
    #code
elif re.match('..15', time):
    # code
elif re.match('..30', time):
    # code
elif re.match('..45', time):
    # code

the . simply means match any char, except for \n, re.match either returns an object or None if there was no match.

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