Convert String to Bytes in Java [duplicate]

Question

Possible Duplicate:
Convert a string representation of a hex dump to a byte array using Java?

I got an MD5 String

de70d4de8c47385536c8e08348032c3b

and I need it as the Byte Values

DE 70 D4 DE 8C 47 38 55 36 C8 E0 83 48 03 2C 3B

This should be similar to Perls pack("H32); function.

So you want to transform the string from this: de70d4de8c47385536c8e08348032c3b to this: DE 70 D4 DE 8C 47 38 55 36 C8 E0 83 48 03 2C 3B? — npinti
– npinti, Commented May 28, 2012 at 13:55
Nearly, I don't want this to be seen as the String in a textfile, but as the bytes. — Moritz
– Moritz, Commented May 28, 2012 at 13:56
Can you write a unit test? I've no idea which data types you mean. — nes1983
– nes1983, Commented May 28, 2012 at 13:56
(Lots of "how do I parse hex in Java" questions - I chose one example.) — Jon Skeet
– Jon Skeet, Commented May 28, 2012 at 13:57

Alex Stybaev · Accepted Answer · 2012-05-28 13:59:35Z

3

you may take a look at Apache Commons Codec Hex.decodeHex()

answered May 28, 2012 at 13:59

Alex Stybaev

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Hakan Serce · Accepted Answer · 2012-05-28 13:57:17Z

2

Loop over the String and use Byte.decode(String) function to fill a byte array.

answered May 28, 2012 at 13:57

Hakan Serce

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2 Comments

dacwe Over a year ago

For example "de" is not parseable by Byte.decode so I don't think it would work.

Hakan Serce Over a year ago

You need to put "0x" as a prefix.

dacwe · Accepted Answer · 2012-05-28 14:06:55Z

1

There are many ways to do this. Here is one:

public static void main(String[] args) {

    String s = "de70d4de8c47385536c8e08348032c3b";

    Matcher m = Pattern.compile("..").matcher(s);

    List<Byte> bytes = new ArrayList<Byte>();
    while (m.find())
        bytes.add((byte) Integer.parseInt(m.group(), 16));

    System.out.println(bytes);
}

Outputs (-34 == 0xde):

[-34, 112, -44, -34, -116, 71, 56, 85, 54, -56, -32, -125, 72, 3, 44, 59]

answered May 28, 2012 at 14:06

dacwe

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juergen d · Accepted Answer · 2012-05-28 14:00:40Z

1

unverified:

String md5 = "de70d4de8c47385536c8e08348032c3b";
byte[] bArray = new byte[md5.length() / 2];
for(int i = 0, k = 0; i < md5.lenth(); i += 2, k++) {
    bArray[k] = (byte) Integer.parseInt(md5[i] + md5[i+1], 16);
}

answered May 28, 2012 at 14:00

juergen d

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