Java ByteBuffer "put" method - preventing buffer overflow

Question

I want to use the put method of the java nio ByteBuffer in the following way:

ByteBuffer small = ByteBuffer.allocate(SMALL_AMOUNT_OF_BYTES);
ByteBuffer big = getAllData();

while (big.hasRemaining()){
    small.put(big);
    send(small);
}

the method put will throw buffer overflow exception, so what i does to fix it was:

 ByteBuffer small = ByteBuffer.allocate(SMALL_AMOUNT_OF_BYTES);
 ByteBuffer big = getAllData();

 while (big.hasRemaining()){
     while (small.hasRemaining() && big.hasRemaining()){
         small.put(big.get());
     }

     send(small);
 }

my question is - is there a better way to do so or at least an efficient way to do what i want?

unwind · Accepted Answer · 2012-05-16 11:34:53Z

5

Well, instead of using the boolean hasRemaining(), you can actually call remaining() to figure out exactly how many bytes are remaining.

Then you could use a small fixed-size intermediate byte array together with the array-based get() and put() methods to transfer "chunks" of bytes, adjusting the number of bytes put into the intermediate buffer based on the amount of remaining space.

answered May 16, 2012 at 11:34

unwind

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