Python and if statement

Question

I'm running a script to feed an exe file a statement like below:

for j in ('90.','52.62263.','26.5651.','10.8123.'):
    if j == '90.':
        z = ('0.')
    elif j == '52.62263.':
        z = ('0.', '72.', '144.', '216.', '288.')
    elif j == '26.5651':
        z = ('324.', '36.', '108.', '180.', '252.')
    else:
        z = ('288.', '0.', '72.', '144.', '216.')

    for k in z:

        exepath = os.path.join('\Program Files' , 'BRL-CAD' , 'bin' , 'rtarea.exe')
        exepath = '"' + os.path.normpath(exepath) + '"'
        cmd = exepath + '-j' + str(el) + '-k' + str(z)

        process=Popen('echo ' + cmd, shell=True, stderr=STDOUT )
        print process

I'm using the command prompt and when I run the exe with these numbers there are times when It doesn't seem to be in order. Like sometimes it will print out 3 statements of the 52.62263 but then before they all are printed it will print out a single 26.5651 and then go back to 52.62263. It's not just those numbers that act like this. Different runs it may be different numbers (A 52.62263 between "two" 90 statements) . All in all, I want it to print it in order top to bottom. Any suggestions and using my code any helpful solutions? thanks!

eduffy · Accepted Answer · 2009-06-19 14:57:07Z

8

z = ('0.') is not a tuple, therefore your for k in z loop will iterate over the characters "0" and ".". Add a comma to tell python you want it to be a tuple:

z = ('0.',)

answered Jun 19, 2009 at 14:57

eduffy

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1 Comment

Tyler Over a year ago

That fixes the 90 but there is still a 26.5651 between the 3rd and 4th 52.62263 statements?

glglgl · Accepted Answer · 2012-12-18 08:11:16Z

6

I think what's happening right now is that you are not waiting for those processes to finish before they're printed. Try something like this in your last 2 lines:

from subprocess import Popen, STDOUT
stdout, stderr = Popen('echo ' + cmd, shell=True, stderr=STDOUT).communicate()
print stdout

edited Dec 18, 2012 at 8:11

glglgl

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answered Jun 19, 2009 at 15:06

John G

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3 Comments

user447688 Over a year ago

Dumb question: what module is Popen()?

SilentGhost Over a year ago

@John: it's a class in subprocess

Tyler Over a year ago

the first 2 k's work fine but for j==26.5651 and 10.8123 the z's are the same as j==52.62263 ??

score 5 · Accepted Answer · 2009-06-19 15:16:39Z

5

What eduffy said. And this is a little cleaner; just prints, but you get the idea:

import os

data = {
    '90.': ('0.',),
    '52.62263.': ('0.', '72.', '144.', '216.', '288.'),
    '26.5651.': ('324.', '36.', '108.', '180.', '252.'),
    '10.8123.': ('288.', '0.', '72.', '144.', '216.'),
}

for tag in data:
    for k in data[tag]:
        exepath = os.path.join('\Program Files', 'BRL-CAD', 'bin', 'rtarea.exe')
        exepath = '"' + os.path.normpath(exepath) + '"'
        cmd = exepath + ' -el ' + str(tag) + ' -az ' + str(data[tag])
        process = 'echo ' + cmd
        print process

edited Jun 19, 2009 at 15:16

answered Jun 19, 2009 at 15:10

user447688

Comments

Kenan Banks · Accepted Answer · 2009-06-19 15:11:09Z

2

Since you've made a few posts about this bit of code, allow me to just correct/pythonify/beautify the whole thing:

for j,z in {
        '90.'       : ('0.',) ,
        '52.62263.' : ('0.',   '72.', '144.', '216.', '288.') ,
        '26.5651.'  : ('324.', '36.', '108.', '180.', '252.') ,
        '10.8123.'  : ('288.', '0.',  '72.',  '144.', '216.')
    }.iteritems():

    for k in z:
        exepath = os.path.join('\Program Files' , 'BRL-CAD', 'bin' , 'rtarea.exe')
        exepath = '"%s"' % os.path.normpath(exepath)
        cmd = exepath + '-j' + str(el) + '-k' + z

        process = Popen('echo ' + cmd, shell=True, stderr=STDOUT )
        print process

answered Jun 19, 2009 at 15:11

Kenan Banks

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