I come across this:-
PHP Error handling: die() Vs trigger_error() Vs throw Exception
and understood that throw exception is better
How can i replace die and use throw exception here in this code:-
<?php
# FileName="Connection_php_mysql.htm"
# Type="MYSQL"
# HTTP="true"
$hostname_db = "localhost";
$database_db = "database";
$username_db = "root";
$password_db = "password";
$db = mysqli_connect($hostname_db, $username_db, $password_db) or die("Unable to connect with Database");
?>
try
{
if ($db = mysqli_connect($hostname_db, $username_db, $password_db))
{
//do something
}
else
{
throw new Exception('Unable to connect');
}
}
catch(Exception $e)
{
echo $e->getMessage();
}
die("Unable to connect with Database"); with your code? Also can you tell me what is @$_POST['variable']
$_POST['variable'] is.//do something because it just need to do connect or show the error...try...catch block.It is documented here https://www.php.net/manual/en/mysqli.error.php
if (mysqli_connect_errno()) {
throw new RuntimeException("Connect failed: %s\n", mysqli_connect_error());
}
$db = mysqli_connect($hostname_db, $username_db, $password_db) or die("Unable to connect with Database"); I have to replace with this $db = mysqli_connect($hostname_db, $username_db, $password_db); if (mysqli_connect_errno()) { throw new RuntimeException("Connect failed: %s\n", mysqli_connect_error()); }