Parse input from string containing ints

Question

I am trying to get input from a string containing ints. So when a user types in the command "getrange(1,12)" I need to read the inital command as a string, and the two numbers inside it as an ints. I was thinking I could do a number of Splits() but I think that might get messy. In addition Split() keeps them as strings I think.

My ultimate goal is to write an IF statement like this:

if("getrange")
{

    while(1 <= 12)
    {
        output.println(MyArray[1])
        1++
    }
}

Any Ideas? I know this is pretty crude, let me know if I need to clarify. Thanks

Bhesh Gurung · Accepted Answer · 2012-01-31 20:35:41Z

2

String input = "getrange(1,12)";
String[] parts = input.split("\\(");
System.out.println("Command: " + parts[0]);
String[] argsParts = parts[1].substring(0, parts[1].indexOf(")")).split(",");
int arg1 = Integer.parseInt(argsParts[0].trim());
int arg2 = Integer.parseInt(argsParts[1].trim());        
System.out.println("Args: " + arg1 + ", " + arg2);

Output:

Command: getrange
Args: 1, 12

answered Jan 31, 2012 at 20:35

Bhesh Gurung

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Comments

RussS · Accepted Answer · 2012-01-31 20:30:41Z

2

 Scanner s = new Scanner(input);
 s.findInLine("getRange\((\\d+),(\\d+)\)");
 MatchResult result = s.match();
 //You should do some error checking here (are there enough matches ...)
 int StartRange == Integer.parseInt(result.group(0));
 int EndRange == Integer.parseInt(result.group(1));

And you can take it from there :)

answered Jan 31, 2012 at 20:30

RussS

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Comments

nolt2232 · Accepted Answer · 2012-01-31 20:30:04Z

1

Use a regular expression to get the numbers and then then do an Integer.parseInt() on the two pieces. The other option which is less ideal would be to do a combo of substring and split to remove the unwanted characters.

answered Jan 31, 2012 at 20:30

nolt2232

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