Determine if a computer has a GPU during runtime in CUDA C

Question

I'm writing code on a GPU enabled machine, but my code needs to be portable to computers without a GPU. So I wrote 2 functions, one that uses only the CPU and one that uses CPU+GPU.

I'm for a conditional compliance code, for example:

if (COMPUTER_HAS_GPU)
    //Run CPU+GPU code  
else  
    //Run CPU only code

Is there anything like this?

Your example suggests you don't want to do this at runtime, but at compile time. The easiest would be to add a define and let the user specify what they want. — Michael Mior
– Michael Mior, Commented Jan 27, 2012 at 15:14
You're right, my example did suggest runtime, but now I changed it to compile time. — user1007692
– user1007692, Commented Jan 27, 2012 at 15:21
@user10007692 I assume you meant your example suggested compile time, but you changed it to runtime. — Michael Mior
– Michael Mior, Commented Jan 27, 2012 at 15:23

Moe · Accepted Answer · 2012-01-27 15:23:45Z

6

You can use cudaGetDeviceCount()

For Example:

int devices = 0; 

cudaError_t err = cudaGetDeviceCount(&devices); 

if (devices > 0 && err == cudaSuccess) 
{ 
    // Run CPU+GPU code
} 
else
{ 
    // Run CPU only code
}

edited Jan 27, 2012 at 15:23

answered Jan 27, 2012 at 15:16

Moe

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Pih · Accepted Answer · 2012-01-27 15:26:33Z

2

You can try to use the cudaGetDeviceCount(*int); function, that gives you how many cuda devices do you have and you can check the error code.

int i;

cudaError_t e = cudaGetDeviceCount(&i);

if (e == cudaErrorNoDevice) {
 // No CUDA device :-(
} else {
 // CUDA device .o/
}

edited Jan 27, 2012 at 15:26

answered Jan 27, 2012 at 15:16

Pih

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