PHP If/Else Multiple Conditionals

Question

From what I've read, if statement conditionals should break as soon as a false is found however:

if(array_key_exists('cool', $_POST) && $_POST['cool'] == 1)

returns an index undefined error. What I want to do is check to see if the key is even there and then check it's value, but the only way I've been able to do that is:

if(array_key_exists('cool', $_POST)) {
  if($_POST['cool'] == 1)

and that means I have to have multiple else blacks as well. Is there anyway to do this with less code?

Use isset()

vascowhite
– vascowhite

2012-01-23 17:49:29 +00:00
Commented Jan 23, 2012 at 17:49 — vascowhite
– vascowhite, Commented Jan 23, 2012 at 17:49

majic bunnie · Accepted Answer · 2012-01-23 17:49:20Z

2

You can use isset which is a language construct as opposed to a function call:

if(isset($_POST['cool']) && $_POST['cool'] == 1)

answered Jan 23, 2012 at 17:49

majic bunnie

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Comments

Luchian Grigore · Accepted Answer · 2012-01-23 17:50:05Z

1

You need to check if the key exists in the array:

if(array_key_exists('cool',$_POST) && $_POST['cool'] == 1)

or use isset().

answered Jan 23, 2012 at 17:50

Luchian Grigore

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1 Comment

ahamilton9 Over a year ago

isset fixed it. Thank you. I must have been mistyping it.

WordsWorth · Accepted Answer · 2012-01-23 17:51:38Z

1

Try this

if(array_key_exists('cool',$_POST) && $_POST['cool'] == 1)

answered Jan 23, 2012 at 17:51

WordsWorth

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