PHP if else condition

Question

somebody help me please,

<?php if ($_POST['jobs'] == 6 || 7 || 8 || 9 && $_POST['sex'] = 'L') {*true statement*} ?>

it is correct? CMIIW. someone please explain how to write if else with array condition. Thanks

which value get in $_POST['jobs']

Ankur Bhadania
– Ankur Bhadania

2014-10-17 06:17:08 +00:00
Commented Oct 17, 2014 at 6:17 — Ankur Bhadania
– Ankur Bhadania, Commented Oct 17, 2014 at 6:17
Use in_array function.

Indrasinh Bihola
– Indrasinh Bihola

2014-10-17 06:17:10 +00:00
Commented Oct 17, 2014 at 6:17 — Indrasinh Bihola
– Indrasinh Bihola, Commented Oct 17, 2014 at 6:17
$_POST['sex'] = 'L' I'm assuming you meant double equals?

SubjectCurio
– SubjectCurio

2014-10-17 06:21:55 +00:00
Commented Oct 17, 2014 at 6:21 — SubjectCurio
– SubjectCurio, Commented Oct 17, 2014 at 6:21

Sledmore · Accepted Answer · 2014-10-17 06:20:47Z

3

I'd advise you to check out the in_array function.

$jobs = array('6', '7', '8', '9');
if (in_array($_POST['jobs'], $jobs) && $_POST['sex'] == 'L')
{
    //Do something.
}

answered Oct 17, 2014 at 6:20

Sledmore

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Comments

Shemil R · Accepted Answer · 2014-10-17 06:21:32Z

0

If $_POST['jobs'] contain only one value, make array with all expected results. After that you can use in_array function for checking whtr the value contains in that array or not.

$resultArray = array('6', '7', '7', '8');
if (in_array($_POST['jobs'], $resultArray ) && $_POST['sex'] == 'L')
{
   //true condition
}

answered Oct 17, 2014 at 6:21

Shemil R

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arif_suhail_123 · Accepted Answer · 2014-10-17 06:21:34Z

0

Try this You have to give value each time when you use ||

<?php if ($_POST['jobs'] == 6 || $_POST['jobs'] == 7 || $_POST['jobs'] ==8 
        || $_POST['jobs'] ==9 && $_POST['sex'] = 'L') {} 
        ?>

answered Oct 17, 2014 at 6:21

arif_suhail_123

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Comments

Jafar · Accepted Answer · 2014-10-17 06:24:48Z

0

You used one equal sign instead of two here :

$_POST['sex'] = 'L'

so that the program always see the condition true and set value of $_POST['sex'] to 'L' .

answered Oct 17, 2014 at 6:24

Jafar

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Ankur Bhadania · Accepted Answer · 2014-10-17 06:27:15Z

0

try this way

<?php 
    $string="6 || 7 || 8 || 9";
    $newarray=explode('||',$string); // $newarray is like array('6', '7', '8', '9');
    if (in_array($_POST['jobs'],$newarray) && $_POST['sex'] == 'L') {*true statement*} 
?>

edited Oct 17, 2014 at 6:27

answered Oct 17, 2014 at 6:21

Ankur Bhadania

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Comments

Graham S. · Accepted Answer · 2014-10-17 06:36:47Z

0

I would do this:

$jobs = array(6, 7, 8, 9);

if ((in_array($_POST['jobs'], $jobs) && (strcmp($_POST['sex'], 'L') == 0)) {
    //Do super cool stuff
}

edited Oct 17, 2014 at 6:36

answered Oct 17, 2014 at 6:28

Graham S.

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