Add strings to List<string[]> list

Question

I'm new to C#, I need to do the following:

I need to declare a List

List<string[]> myList = new List<string[]>();

Now the conditions and adding to the list should work as follows (in pseudo code):

for int i = 0 to N
if nNumber == 1 add string[i] to myList[0]
else to myList[1]

In the end, I would have 2 members in my list, each member having several strings.

I am not sure how I can add these strings to the members as the method List(Of T).Add inserts members to the list and I do not want this.

Your list currently holds string[] which are string arrays. It's not clear if this is intended or you meant to hold a list of strings List<string>. — BoltClock
– BoltClock, Commented Nov 24, 2011 at 11:47
memebr 1 myList[0] will have string1, string2, etc, and the second member myList[1] will having another bunch of strings — Sunscreen
– Sunscreen, Commented Nov 24, 2011 at 11:50
@Sunscreen: Why use an array? will it always have exactly 2 members? — reinierpost
– reinierpost, Commented Nov 24, 2011 at 11:51
I just need 2 members. If there is another imlementation is very welcome... — Sunscreen
– Sunscreen, Commented Nov 24, 2011 at 12:05

mjwills · Accepted Answer · 2011-11-24 11:52:35Z

3

        var myList = new List<string>[] { new List<string>(), new List<string>() }; 

        for (int i = 0; i <= 12; i++)
        {
            if (i == 1)
                myList.Last().Add(i.ToString());
            else
                myList.First().Add(i.ToString());
        }

answered Nov 24, 2011 at 11:52

mjwills

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Heinzi · Accepted Answer · 2011-11-24 11:54:05Z

3

From what I can see, you don't want a list of string arrays, you want a 2-element array of lists of strings:

var myList = new List<string>[] { new List<string>(), new List<string>() };

Now you should be able to implement the algorithm exactly as you specified.

edited Nov 24, 2011 at 11:54

answered Nov 24, 2011 at 11:48

Heinzi

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7 Comments

Sunscreen Over a year ago

It sounds promissing, and how can I add? possibly like that myList[0].Add() ??

Sunscreen Over a year ago

Though I am using C# 2.0 and I cannot declare varcutom type... i sthere away to do it?

Heinzi Over a year ago

@Sunscreen: Then replace var with List<string>[].

Sunscreen Over a year ago

Again compalins that Iit cannot convert List<string>[] to List<string>[]

Heinzi Over a year ago

@Sunscreen: Can you copy the message in verbatim? Cannot convert List<string>[] to List<string>[] doesn't make sense...

|

Elias Hossain · Accepted Answer · 2011-11-24 12:46:56Z

3

This can be also performed as List of List of string as below:

    List<List<string>> strList = new List<List<string>>();
    for (int i = 0; i < N; i++)
    {
        if (nNumber == 1)
            strList[0].Add(i.ToString());
        else
            strList[1].Add(i.ToString());
    }

answered Nov 24, 2011 at 12:46

Elias Hossain

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Comments

octopusgrabbus · Accepted Answer · 2016-05-05 20:48:58Z

In my csv parsing class, I have the following defined

enum gic_rpt_columns { AGYDIV, STS, GICID, LASTNAME, FIRSTNAME, COVERAGE, DESCRIPTION , PREMIUM, RUNDATE, BILMO, EMPLOYERPERCENT };

public class csv_parser
{
    .
    .
    .
    private string[]        m_column_headings;
    List<string[]>          m_csv_array = new List<string[]>();
    .
    .
    .

The following code will add my column headings and then the rows in the csv file

               using (TextFieldParser parser = new TextFieldParser(m_csv_path))
                {
                    parser.TextFieldType = FieldType.Delimited;
                    parser.SetDelimiters(",");

                    if (!parser.EndOfData)
                    {
                        m_column_headings = parser.ReadFields();
                        m_csv_array.Add(m_column_headings);
                    }

                    while (!parser.EndOfData)
                    {
                        string[] fields = parser.ReadFields();
                        m_csv_array.Add(fields);
                        m_row_count++;
                    }
                }

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