Loop over an array of csv strings containing quoted values then return the first value from each csv string

Question

I am trying loop over an array with a foreach().

When I tested the code below,

$aa = array("'a1','a2'","'b1','b2'","'c1','c2'");
foreach($aa as $bb){
    $cc = array($bb);//var_dump($cc);  (1) { [0]=> string(9) "'a1','a2'" }...
    foreach($cc as $dd){
        echo $dd.'<br />';
        break;
    }
}

It will output:

'a1','a2'
'b1','b2'
'c1','c2'

But I want a1,b1,c1.

Wrong with $cc = array($bb)...

What is the problem?

You store a string in an array and then echo the only element (the string) in that array=) — Cyclonecode
– Cyclonecode, Commented Nov 19, 2011 at 22:15

Oroboros102 · Accepted Answer · 2011-11-19 22:15:46Z

3

You have one level array, not two. Elements are just strings for php, not arrays. That's why your code doesn't work.

Replace your $cc = array($bb) string with smth like this:

$cc = explode(',', $bb);
foreach($cc as $dd){
    echo trim($dd, "'").'<br />';
    break;
}

answered Nov 19, 2011 at 22:15

Oroboros102

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1 Comment

Nonym Over a year ago

Right! In context, the value 'a1','a2' could be further split into an array and so exploding it made the a1, b1, c1 easily accessible :)

mickmackusa · Accepted Answer · 2024-09-19 12:18:06Z

0

Iterate over you single quote wrapped csv strings and return the first value from each string after parsing.

Code: (Demo)

$aa = [
    "'a1','a2'",
    "'b1','b2'",
    "'c1','c2'"
];
var_export(
    array_map(
        fn($csv) => str_getcsv($csv, ',', "'")[0],
        $aa
    )
);

If you require a lone delimited string, just call implode() on the result array above.

answered Sep 19, 2024 at 12:18

mickmackusa♦

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