Dynamically populate a subarray inside of an array declaration

Question

I'm trying to create an array inside an array, using a for loop - here's my code:

array(
    'label' => 'Assign to user',
    'desc' => 'Choose a user',
    'id' => $prefix . 'client',
    'type' => 'radio'
    'options' => array( 
        foreach ($clients as $user) {
         $user->user_login => array (  
            'label' => $user->user_login,  
            'value' => $user->user_login,
            ), 
        }
    )
)

Unfortunately this gives me a

"Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting ')'"

For the line:

'options' => array(

I'm at a bit of a loss as to what has gone wrong. $clients is defined elsewhere, so that is not the problem.

Marc B · Accepted Answer · 2013-01-22 14:57:41Z

26

That's invalid syntax. You'd have to build the "parent" portions of the array first. THEN add in the sub-array stuff with the foreach loop:

$foo = array(
    'label' => 'Assign to user',
    'desc' => 'Choose a user',
    'id' => $prefix.'client',
    'type' => 'radio',
    'options' => array()
);

foreach ($clients as $user) {
    $foo['options'][] = array (  
        'label' => $user->user_login,  
        'value' => $user->user_login,
    );
}

edited Jan 22, 2013 at 14:57

answered Jan 21, 2013 at 19:58

Marc B

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2 Comments

user319940 Over a year ago

Unfortunately this doesn't seem to work for me as the array foo, is in an array itself which gives the error Parse error: syntax error, unexpected T_FOREACH, expecting ')'

dhaupin Over a year ago

You don't need to make 'options' an array() if there is a chance it won't be filled. That may throw off some parsers to see an empty value (ie, schema json-ld).

ste · Accepted Answer · 2013-01-21 19:56:41Z

2

You use foreach to access the data, not define it.

Try this:

array(
    'label' => 'Assign to user',
    'desc' => 'Choose a user',
    'id' => $prefix.'client',
    'type' => 'radio'
    'options' => $clients
    )

If you need to change the structure of the data for 'options', do this before defining the primary array.

answered Jan 21, 2013 at 19:56

ste

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5 Comments

user319940 Over a year ago

With this approach, how would I go about making $clients be an array of arrays? sorry if this sounds a little dense!

ste Over a year ago

Define $clients first [code]$clients = array(array('oneval', 'two'), array('another', 'another'));[/code] then just include $clients in your primary array

user319940 Over a year ago

but I need to get the values by using a foreach loop as clients is used for a wordpress query: $clients = get_users();

ste Over a year ago

Then make sure you've populated an array with the structure you expect and assign it to $clients - or try Marc's answer; same approach, different order

user319940 Over a year ago

Not quite sure what you mean by that, unfortunately Marc's code does not work in my situation (see comment), thanks for your help though.

Cody Covey · Accepted Answer · 2013-01-21 19:58:45Z

1

You cannot use the foreach in the definition of the array. You can however put the $clients variable in the array itself or you can foreach outside the array to build the array to be inserted at the options key

answered Jan 21, 2013 at 19:58

Cody Covey

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Comments

mickmackusa · Accepted Answer · 2024-09-19 16:12:33Z

0

array_map() will elegantly allow you to dynamically populate the subarray without needing to break out of tour original array. Demo

$result = [
    'label' => 'Assign to user',
    'desc' => 'Choose a user',
    'id' => $prefix . 'client',
    'type' => 'radio',
    'options' => array_map( 
        fn($user) => [  
            'label' => $user->user_login,  
            'value' => $user->user_login,
        ], 
        $clients
    )
];

answered Sep 19, 2024 at 16:12

mickmackusa♦

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