How do I call a behavior definition custom action?

Question

Issue: custom action not called or triggered in Fiori app.

Action taken: I was trying to trigger the custom action from the behavior definition when a button is pressed in my Fiori app.

I have a Fiori app which is created thru "connect to a system", OData service which is also connected to the Fiori app.

In Odata service has a behavior definition and class.

Inside the class, there is a private method called read_file.
Inside the behavior definition I tried to call the read_file using the syntax:

action read_file result [0..*} $self

In my Fiori app I have a submit button that should trigger the custom action using this code:

View.xml:

<Button text="Submit" press="onSubmit"/>

Main.controller.js:

var oModel = this.getView().getModel();
var oBindingContext = this.getView().getBindingContext();

var oAction = oModel.bindContext("read_file()", oBindingContext);

oAction.execute().then(function(oResult) {
 MessageToast.show("File read success");
 console.log(oResult);
}).catch(function(oError) {
 MessageBox.error(oError.message);
});

why don't you enable the action in your fiori using annotations? @UI.lineItem: [{ position: 10 }, { type: #FOR_ACTION, dataAction: 'read_file', label: 'Read File'}] — Marc
– Marc, Commented Sep 6 at 11:25

York Chen · Accepted Answer · 2025-11-17 08:35:57Z

-2

var oAction = oModel.bindContext("/read_file(...)", oBindingContext);

answered Nov 17 at 8:35

York Chen

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