Update or insert same node from the other XML using xslt

Question

I have a source xml that contains a list of element which may or may not exists in target xml and target xml has some other xml element. The requirement is to update the second xml with the rule :loop at the element in the first xml. if node exists in the target xml then update the value, otherwise add the node to the target xml. I could hard code on field name f1 and f2 and f3 for my example below. But I am wondering if it is possible to make it generic so to have a piece of transformation code really saying "loop at the element in the first xml. if node exists in the target xml then update the value, otherwise add a new node" without coding on each node name?

Parameter XML

<root>
<f1>1<f1>
<f2>2<f2>
<f3>3<f3>
</root>

input XML

<root>
<f1>a<f1>
<FY>Y<fY>
<fz>Z<fz>
</root>

output XML

<root>
<f1>1<f1>
<f2>2<f2>
<f3>3<f3>
<FY>Y<fY>
<fz>Z<fz>
</root>

I am using XSLT Version 1.0

<xsl:param name="SourceData" />
    <xsl:variable name="Source_xml" select="parse-xml($SourceData)" />

and then

 <xsl:template match="f1">
  <f1><xsl:value-of select="$Source_xml//f1"/></f1>
 </xsl:template>
 <xsl:template match="f2">
  <f2><xsl:value-of select="$Source_xml//f2"/></f2>
 </xsl:template>
 <xsl:template match="f3">
  <f3><xsl:value-of select="$Source_xml//f3"/></f3>
 </xsl:template>

The claim "I am using XSLT Version 1.0" seems complete nonsense if the XSLT code use a function like parse-xml which is a function only introduced in XPath 3 and therefore usually only supported by XSLT 3 processors. — Martin Honnen
– Martin Honnen, Commented Sep 28, 2024 at 17:09
Try this as your starting point: stackoverflow.com/a/31402704/3016153. — michael.hor257k
– michael.hor257k, Commented Sep 28, 2024 at 17:26
While asking an XSLT question you need to provide a minimal reproducible example: (1) Well-formed input XML with all relevant namespaces. (2) Your logic, and complete executable XSLT stylesheet that tries to implement it. (3) Desired output, based on the sample XML in the #1 above. (4) XSLT processor and its conformance with the XSLT standards: 1.0, 2.0, 3.0, or 4.0. — Yitzhak Khabinsky
– Yitzhak Khabinsky, Commented Sep 29, 2024 at 0:19

Michael Kay · Accepted Answer · 2024-09-28 23:32:23Z

2

Given that (if parse-xml() works) you are using XSLT 3.0, you can use the xsl:merge instruction:

<root>
  <xsl:merge>
    <xsl:merge-source 
           for-each-source="'doc1.xml', 'doc2.xml'"
           select="/*/*">
      <xsl:merge-key select="name()" order="ascending"/>
    </xsl:merge-source>
    <xsl:merge-action>
      <xsl:copy-of select="current-merge-group()[1]"/>
    </xsl:merge-action>
  </xsl:merge>
</root>

This assumes that both inputs are sorted by name. If not, there is an option sort-before-merge to force this.

answered Sep 28, 2024 at 23:32

Michael Kay

165k11 gold badges97 silver badges173 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Update or insert same node from the other XML using xslt

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related