Swift Compiler Error when build ios app on Xcode

Question

Firstly, I was using xcode version 13.2.1 and I have a problem when trying to build my ios App in terminal / xcode, here is the error response :

/Users/user/.pubcache/hosted/pub.dev/shared_preferences_foundation-2.3.0/ios/Classes/SharedPreferencesPlugin.swift:58:22: Variable binding in a condition requires an initializer

and here is the full function that get error :

func getAllPrefs(prefix: String, allowList: [String]?) -> [String: Any] {
    var filteredPrefs: [String: Any] = [:]
    var allowSet: Set<String>?;
    if let allowList {
      allowSet = Set(allowList)
    }
    if let appDomain = Bundle.main.bundleIdentifier,
      let prefs = UserDefaults.standard.persistentDomain(forName: appDomain)
    {
      for (key, value) in prefs where (key.hasPrefix(prefix) && (allowSet == nil || allowSet!.contains(key))) {
        filteredPrefs[key] = value
      }
    }
    return filteredPrefs
  }

and the error comes from this specific function :

    if let allowList {
      allowSet = Set(allowList)
    }

I never use if let function, so I don't know how to solve this swift error. Can someone tell me how can I solved this?

I don't get any errors when building this code in a playground. Edit, building it online with an older compiler version (5.6) does generate the same error message — Joakim Danielson
– Joakim Danielson, Commented Jul 6, 2023 at 7:28
@JoakimDanielson I edit my post with picture of the error, if you get that error too. How do you analyze that problem? — Dimas Satrya
– Dimas Satrya, Commented Jul 6, 2023 at 7:33

Joakim Danielson · Accepted Answer · 2023-07-06 07:37:20Z

1

Apparently this has been fixed in newer versions of swift but here I would replace the if with

allowSet = allowList == nil ? [] : Set(allowList!)

or perhaps even better

var allowSet = Set<String>()

if allowList != nil {
    Set(allowList!)
}

and a third option :)

var allowSet = allowList == nil ? Set<String>() : Set(allowList!)

answered Jul 6, 2023 at 7:37

Joakim Danielson

53k5 gold badges36 silver badges79 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Sweeper · Accepted Answer · 2023-07-06 07:50:55Z

0

You are trying to use the feature "if let shorthand for shadowing an existing optional variable". This is implemented in Swift 5.7. The Xcode version you are using - 13.2 - only supports Swift 5.5.2. See: https://swiftversion.net/

The lowest Xcode version that supports Swift 5.7 is 14.0. You can update to that version to fix the error.

You can also rewrite the code. In addition to Joakim Danielson's suggestions, you can also do:

var allowSet = allowList.map(Set.init) ?? []

answered Jul 6, 2023 at 7:50

Sweeper

292k23 gold badges260 silver badges437 bronze badges

Collectives™ on Stack Overflow

Swift Compiler Error when build ios app on Xcode

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related