How to create a constructor with a parameter with Roslyn?

Question

I'm generating classes from an Open API specification and need to create a constructor that accepts a parameter and sets it to a field. How do I do that with Roslyn?

Mikael Dúi Bolinder · Accepted Answer · 2022-01-05 19:12:09Z

1

I ended up using this code to create a constructor that accepts a parameter and sets it to a field:

SyntaxFactory.ConstructorDeclaration("MyClass")
    .AddParameterListParameters(
        SyntaxFactory.Parameter(SyntaxFactory.Identifier("myParameter"))
            .WithType(SyntaxFactory.ParseTypeName("string")))
    .WithBody(SyntaxFactory.Block(SyntaxFactory.ParseStatement($"_myField = myParameter;")))
    .AddModifiers(SyntaxFactory.Token(SyntaxKind.PublicKeyword));

The generated constructor for this code is:

public MyClass(string myParameter)
{
     _myField = myParameter;
}

answered Jan 5, 2022 at 19:12

Mikael Dúi Bolinder

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