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I am a beginner of C++ with Python background. I have some ambiguity about the process of obtaining instance attributes in Python classes and C++ classes.

As follows, I list two classes that have the same function in Python and C++ respectively.

My problem is that I am used to using self parameters to distinguish class attributes and instance attributes, and to ensure that instance attributes between different instances do not interfere with each other. But I do not know how C++ can do this without self parameters.enter image description here

I hope someone can explain in detail how C++achieves “self” without self, and what happens in under the hood?

Thanks

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    Because C++ is not Python. It's not really clear what sort of answer you are expecting here. Commented Nov 23, 2022 at 2:46
  • It actually does have a self parameter, but this is hidden from the coder Commented Nov 23, 2022 at 2:46
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    Python is in the minority of languages that expose the this/self parameter, a lot of languages (C++, Java, JavaScript, C#, Ruby) don't Commented Nov 23, 2022 at 2:47
  • C++ has scoping rules about how names are resolved which allow it to decide when a variable is referring to an instance variable of the class, once that is decided at compilation time, then attributes work much the same (well, not exactly the same). C++ has quite different scoping rules from Python's scoping rules. Commented Nov 23, 2022 at 2:48
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    If your properties were public, you could check dog1.m_name and dog2.m_name Commented Nov 23, 2022 at 3:00

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c++ just doesn't write "self" explicitly, maybe you need to learn about the keyword "this".

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