Powershell Simple Array output incorrect? [duplicate]

Question

$nameonly =  @("") * 20 

$i=1 
do 
{
    $nameonly[$i] = "A$i" 
    $i++
}
until ($i -eq 10)

write-host "$nameonly[4]"

When i run the code i expect the output to be: A4 but instead i get:

A1 A2 A3 A4 A5 A6 A7 A8 A9 [4]

`

PowerShell stops the parsing of expressive tokens such as the [..] in a string. The way around that, you wrap the expression inside the string with a sub-expression operator $(..). Switch "$nameonly[4]", to this "$($nameonly[4])". You can also just leave out the quotes. — Abraham Zinala
– Abraham Zinala, Commented Jun 12, 2022 at 4:40

alfi · Accepted Answer · 2022-06-12 03:23:59Z

2

Try removing the quotation marks in your final command. So it should be write-host $nameonly[4] This will get you the indexed value in position 4 of the array.

You can also skip the write-host command. Invoking the variable $nameonly[4] will output to the console.

If you use quotation marks then it will convert the whole array into a string and output the entire array content as a string object.

answered Jun 12, 2022 at 3:23

alfi

314 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

BrandyPuff Over a year ago

Thank you so much, this was driving me crazy! I'm still learning the idiosyncrasies of Powershell.

mklement0 Over a year ago

Good advice, but note that the only problem with BrandyPuff's attempt was neglecting to enclose the expression $nameonly[4] in $(...) inside "..." - see the linked duplicate.

Collectives™ on Stack Overflow

Powershell Simple Array output incorrect? [duplicate]

1 Answer 1

2 Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Linked

Related