Try/except for check string in Python

Question

I would like to use Try/ecept to check if a string is really a string. I made the following code:

nome = input('Name: ')
try:
    if not nome.isalpha() or nome == '':
        raise ValueError('Invalid!')
    else:
        print(f'Name {nome} valid.') 
except ValueError as e:
    print(f'Error: {e}')

But, I would like to do it without using the raise command, just try/except.

Can anyone help me? I thank you.

try/except requires something to raise the exception. There's no built-in function that raises an exception for non-alpha strings, so you have to raise it explicitly. — Barmar
– Barmar, Commented Apr 18, 2022 at 20:57
You would need to provide your own assertion method that raises internally. e.g. def assert_isalpha_non_empty — flakes
– flakes, Commented Apr 18, 2022 at 21:01

Kurt · Accepted Answer · 2022-04-18 21:03:39Z

1

The only way to trigger an exception without raising it yourself is to attempt something invalid, such as this:

nome = input('Name: ')
try:
    f = float(nome)
except ValueError as e:
    print('Is alpha')
else:
    print('Not alpha')

Here I try to convert the input to a float, and if there are any alpha characters in the value, it will raise the ValueError exception.

answered Apr 18, 2022 at 21:03

Kurt

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