numpy interation in python without FOR loop [duplicate]

Question

i have a following numpy array. array([11, 11, 51, 11, 11, 51, 51, 11, 11, 51]) which has a shape (10,)

I want to make it to array([[11], [11], [51], [11], [11], [51], [51], [11], [11], [51]]) and shape should be (10,1).

One way to do it using the for loop, but i think which is not good way to get this done.

can someone suggest a more proper way?

thanks

@MichaelSzczesny it is like this-: 1. i corvert into list. then make list of lists. and then convert it to numpy array — Coder
– Coder, Commented Mar 9, 2022 at 16:01

Salvatore Daniele Bianco · Accepted Answer · 2022-03-09 15:49:52Z

4

a = np.array([11, 11, 51, 11, 11, 51, 51, 11, 11, 51])
a = a.reshape(-1,1)

(-1,1) means that you want the second shape to be exactly 1 and the first shape will be inferred from the length of the array.

answered Mar 9, 2022 at 15:43

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