I want to save ALL ERRORS into a file which means the errors outside an exception, also get in the log file.
for example import some module and in the begining of a script, set it to save the errors; something like this:
import blob
blob.save_errors(filename)
try:
lst = ['a']
print(lst[2]) # save this Error
except:
pass
print(2/0) # also save this error
There is no easy automatic way to process all the exception, it contradict with exception handling idea.
One of solutions: we can log all uncatched exceptions like this way:
import sys
import logging
logger = logging.getLogger(__name__)
handler = logging.StreamHandler(stream=sys.stdout)
logger.addHandler(handler)
def handle_exception(exc_type, exc_value, exc_traceback):
if issubclass(exc_type, KeyboardInterrupt):
sys.__excepthook__(exc_type, exc_value, exc_traceback)
else:
logger.critical("Exception occured:", exc_info=(exc_type, exc_value, exc_traceback))
sys.excepthook = handle_exception
# Just to test
if __name__ == "__main__":
raise Exception("Something happend!")
And to log all handled exception we need to all logging in except block:
try:
...
except:
logger.error("Exception occured:", exc_info=(exc_type, exc_value, exc_traceback))
...
Other way to deal with exception is to handle them in top-level function. All non-handled exceptions from downstream functions will be processed in top-level except block:
def my_main_func():
try:
run_my_application_logic()
except:
# Logging
logger.error("Exception occured:", exc_info=(exc_type, exc_value, exc_traceback))
def run_my_application_logic():
first_step_of_app()
second_step_of_app()
third_step_of_app()
if __name__ == "__main__":
my_main_func()
looger can write log to file. You just need to properly configure logger. stackoverflow.com/questions/6386698/…