I've got a multidimensional array, like so:
let = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9]
]
I need to find the index of array in which element "6" is, which in this case is index 1 as it is in second array.
Any idea how to find it? So far I've got
let theIndex = groupedButtons.map(group => {
group.findIndex(group.forEach(e => {
e === 6
} ))
})
Here's a one liner solution using findIndex and some
let x = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9]
];
const result = x.findIndex(item => item.some(number => number === 6));
console.log(result)This will return the index you are looking for:
let matrix = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9]
]
function find(matrix, item) {
return matrix.findIndex(row => row.indexOf(item) !== -1);
}
console.log(find(matrix, 6));This will return you both row and column index
let matrix = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9]
]
function find2d(matrix, item) {
let ix = 0, col = -1;
while (ix < matrix.length && (col = matrix[ix].indexOf(item)) === -1) ix++;
return ix === matrix.length ? undefined : [ix, col];
}
console.log(find2d(matrix, 6));for one level nested array this function will work good
let arr = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9]
]
function findIndex(arr,val){
let result = null
arr.forEach((each,i)=>{if(each.indexOf(val)>=0){result=i}})
return result
}
console.log(findIndex(arr,6))
let data = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9]
];
const numToFind = 6;
let index = -1;
data.forEach((x, i) => {
if(x.some(n=>n==numToFind)){
index = i;
}
});
console.log(index);