How to loop through xml elements using xsl

Question

I have a scenario like this in xml:

<ViewFields>
  <FieldRef Name="Planing Status" />
  <FieldRef Name="Resource Status" />
  <FieldRef Name="Development Status" />
  <FieldRef Name="Testing Status" />
</ViewStatus>

I have to loop through this in xsl, I followed below:

<xsl:template name="FieldRef_body.Status" match="FieldRef[@Name=/ViewFields/FieldRef[1]]" mode="body">

IT'S NOT RETURNING ANY THING @Name variable i am using several places in this section. I want to assign FieldRef values to @Name variable through loop.

Good question, +1. See my answer for explanation of two of the problems in your code and for providing a clear solution. — Dimitre Novatchev
– Dimitre Novatchev, Commented Jul 31, 2011 at 16:00
Well in your posted XML sample all FieldRef elements are empty so @Name=/ViewFields/FieldRef[1] does not select anything as no Name attribute is empty as well. Otherwise I can't help as your question is not very clear. You might want to post a sample of the result you want to generate with XSLT for the input sample you posted, then we can suggest appropriate XSLT code. With XSLT/XPath @Name is not a selecting a variable, rather it selects an attribute of the name Name. — Martin Honnen
– Martin Honnen, Commented Jul 31, 2011 at 16:01
Dimitre was pretty ambitious in giving you a solution that involved guessing what your problem is. He was also very generous in giving you +1 for the question. As for me, I can see why your code doesn't do anything, but you haven't said clearly what you want it to do, so I cant' tell you how to correct it. — Michael Kay
– Michael Kay, Commented Jul 31, 2011 at 19:22
How can i loop through to get the FieldRef Name values in XSL..! — SP10
– SP10, Commented Jul 31, 2011 at 20:21
Please visit this url for clear post. stackoverflow.com/questions/6891949/… — SP10
– SP10, Commented Jul 31, 2011 at 20:22

Dimitre Novatchev · Accepted Answer · 2011-07-31 15:59:45Z

2

<xsl:template name="FieldRef_body.Status" 
     match="FieldRef[@Name=/ViewFields/FieldRef[1]]" mode="body">

There are two things to note here:

The match attribute contains an XPath expression that, when applied on the provided XML document, selects no node at all. It is supposed to select an element named FieldRef the string value of whose Name attribute is equal to the string value of the first FieldRef child of the ViewFields top element. However, none of the FieldRef elements in the XML document have any (non-empty) string value. On the other side, the string values of all Name attributes are non-empty. My guess is that you wanted: match="FieldRef[@Name=/ViewFields/FieldRef[1]/@Name]"
Any template in a (non-anonymous) mode isn't considered by the XSLT processor for selection if its mode is different from the current mode.

As the initial mode in XSLT 1.0 (and in XSLT 2.0) is the empty (anonymous) mode, the only way to make a template in a non-anonymous mode considered for selection is to explicitly specify the mode on an <xsl:apply-templates> instruction.

This transformation:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="/">
     <xsl:apply-templates select="*/*" mode="body"/>
 </xsl:template>

 <xsl:template match="FieldRef[@Name=/ViewFields/FieldRef[1]/@Name]"
               mode="body">
  <xsl:value-of select="@Name"/>
 </xsl:template>
</xsl:stylesheet>

produces this result, showing that the template is selected for processing:

Planing Status

answered Jul 31, 2011 at 15:59

Dimitre Novatchev

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6 Comments

SP10 Over a year ago

Thank you and appreciate your quick reply, let me give it a try.

SP10 Over a year ago

Hi Dimitre I have tried your suggestion, it's not working out. Let me explain the problem in detail. I am trying to LOOP through the XML for Status(Name Attribute of xml) for each record and show a different image for each status. This should happen for all the four named columns in the xml. I think I have to use for-each to loop through the xml, for all the records for all the columns. Can you please let me know how to solve this. SharePoint list has these columns. Please see the following post for rest of the issue.

SP10 Over a year ago

SP10 Over a year ago

I have the following XSL code <xsl:template name="FieldRef_body.Status" match="FieldRef[@Name=/ViewFields/FieldRef[1]/@Name]" mode="body"> <xsl:param name="thisNode" select="."/> <xsl:choose> <xsl:when test="$thisNode/@*[name()=current()/@Name] = 'Completed'"> <img src="IMNON.png" alt="Status: {$thisNode/@Status}"/> </xsl:when> <xsl:otherwise> <img src="IMNBUSY.png" alt="Status: {$thisNode/@Status}"/> </xsl:otherwise> </xsl:choose> </xsl:template>

Dimitre Novatchev Over a year ago

@user547077: Please, edit your question with clear and legible description of the problem. Bear in mind next time you are going to ask a question, to specify it in a very clear and proper way. Show: 1) The exact XML document. 2) What the processing must return -- the exact and complete result. 3) What are the rules/constraints for the transformation.

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