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I have a list with numerical and string values, like this:

vals = ["1", "2", "A"]

I want to replace all sting values in this list with "0". So that the new list is: ["1", "2", "0"].

Why does not this work?

[i for i in vals if str(i).isnumeric() else "0"]
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3 Answers 3

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Your syntax is invalid. While using if and else in list comprehension, they should come before for loop

vals = ["1", "2", "A"]
new=[i if str(i).isnumeric() else '0' for i in vals]
print(new)
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That's a wrong syntax for comprehension, the if else condition should be checked before for if you want to have the values conditionally:

>>> [i if str(i).isnumeric() else "0" for i in vals ]
['1', '2', '0']

But if you want to have only the values that satisfy the condition, then only you can have if after for <item> in <iterator> without the else part, which is similar to filter builtin:

>>> [i for i in vals if str(i).isnumeric()]
['1', '2']
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This is not how .isnumeric() is used. Instead, use .isdigit():

[i for i in vals if str(i).isdigit() else "0"]
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