string into a list in Python

Question

I have a str that contains a list of numbers and I want to convert it to a list. Right now I can only get the entire list in the 0th entry of the list, but I want each number to be an element of a list. Does anyone know of an easy way to do this in Python?

for i in in_data.splitlines():
    print i.split('Counter32: ')[1].strip().split()

my result not i want

['12576810']\n['1917472404']\n['3104185795']

my data

IF-MIB::ifInOctets.1 = Counter32: 12576810
IF-MIB::ifInOctets.2 = Counter32: 1917472404
IF-MIB::ifInOctets.3 = Counter32: 3104185795

i want result

['12576810','1917472404','3104185795']

It depends on the layout of the string. if it's just "4 8 15 16 23 42", then making it into a list is easy. If there's a lot of extra junk in the string, then it is harder. — Kevin
– Kevin, Commented May 4, 2012 at 13:13

Abhijit · Accepted Answer · 2012-05-04 13:18:06Z

8

Given your data as

>>> data="""IF-MIB::ifInOctets.1 = Counter32: 12576810
IF-MIB::ifInOctets.2 = Counter32: 1917472404
IF-MIB::ifInOctets.3 = Counter32: 3104185795"""

You can use regex where the intent is more clear

>>> import re
>>> [re.findall("\d+$",e)[0] for e in data.splitlines()]
['12576810', '1917472404', '3104185795']

or as @jamylak as pointed out

re.findall("\d+$",data,re.MULTILINE)

Or str.rsplit which will have a edge on performance

>>> [e.rsplit()[-1] for e in data.splitlines()]
['12576810', '1917472404', '3104185795']

answered May 4, 2012 at 13:18

Abhijit

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3 Comments

jamylak Over a year ago

Instead of using data.splitlines() for the regex version you can do. re.findall("\d+$",data,re.MULTILINE)

Abhijit Over a year ago

@jamylak: Aha nice, I forgot. THanks

a1my Over a year ago

data Each line have '\n', Your answer is not I ultimately want.

Daren Thomas · Accepted Answer · 2012-05-04 14:13:42Z

5

You are already quite far. Based on the code you have, try this:

result = []
for i in in_data.splitlines():
    result.append(i.split('Counter32: ')[1].strip())
print result

you could also do:

result = [i.split('Counter32: ')[1].strip() for i in in_data.splitlines()]

Then, you can also go and look at what @Abhijit and @KurzedMetal are doing with regular expressions. In general, that would be the way to go, but I really like how you avoided them with a simple split.

edited May 4, 2012 at 14:13

answered May 4, 2012 at 13:17

Daren Thomas

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1 Comment

yak Over a year ago

Unmatched parentheses in line 3.

KurzedMetal · Accepted Answer · 2012-05-04 13:18:07Z

2

My best try with the info you gave:

>>> data = r"['12576810']\n['1917472404']\n['3104185795']"
>>> import re
>>> re.findall("\d+", data)
['12576810', '1917472404', '3104185795']

you could even convert it to int or long if necesary with map()

>>> map(int, re.findall("\d+", data))
[12576810, 1917472404, 3104185795L]
>>> map(long, re.findall("\d+", data))
[12576810L, 1917472404L, 3104185795L]

answered May 4, 2012 at 13:18

KurzedMetal

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Comments

rh0dium · Accepted Answer · 2012-05-04 13:20:52Z

2

This is how I'd do it.

data="""IF-MIB::ifInOctets.1 = Counter32: 12576810 ... IF-MIB::ifInOctets.2 = Counter32: 1917472404 ... IF-MIB::ifInOctets.3
= Counter32: 3104185795"""

[ x.split()[-1] for x in data.split("\n") ]

answered May 4, 2012 at 13:20

rh0dium

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Comments

Ashwini Chaudhary · Accepted Answer · 2012-05-04 13:40:43Z

1

with open('in.txt') as f:
 numbers=[y.split()[-1] for y in f]
print(numbers)      

  ['12576810', '1917472404', '3104185795']

or:

with open('in.txt') as f:
    numbers=[]
    for x in f:
        x=x.split()
        numbers.append(x[-1])
print(numbers)  

['12576810', '1917472404', '3104185795']

edited May 4, 2012 at 13:40

answered May 4, 2012 at 13:17

Ashwini Chaudhary

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1 Comment

yak Over a year ago

.split() removes whitespace at the start and end of string. The .rstrip() call is redundant.

DaClown · Accepted Answer · 2012-05-04 18:03:24Z

0

result = [(item[(item.rfind(' ')):]).strip() for item in list_of_data]

A variant using list comprehension. Iterator over all line of data, find the last index of a blank, cut down the strip from last found blank position to it's end, strip the resulting string (erase possible blanks) and put the result in a new list.

    data = """F-MIB::ifInOctets.1 = Counter32: 12576810
IF-MIB::ifInOctets.2 = Counter32: 1917472404
IF-MIB::ifInOctets.3 = Counter32: 3104185795"""
    result = [ (item[(item.rfind(' ')):]).strip() for item in data.splitlines()]
    print result

Result:

['12576810', '1917472404', '3104185795']

edited May 4, 2012 at 18:03

answered May 4, 2012 at 13:51

DaClown

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2 Comments

a1my Over a year ago

in_error,in_data = commands.getstatusoutput(in_cmd) if in_error != 0: print "Critical - cmd is error!! pls check!!!" else: for e in in_data.splitlines(): print e.rsplit()[-1]

DaClown Over a year ago

I didn't specify the input and wrote 'list_of_data' instead, that's right. It's not the best solution, I see that now, but it's short and works.

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