fetch all github repo by Github api v3 and javascript

Question

I discovered that by default the API responds with 30 repos.

May I know how should I use for loop to retrieve all repos?

const axios = require('axios');
const repoUrl = `https://api.github.com/users/USERNAME/repos`;

access_token = "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx"
// console.log
const config = {
    headers: {Authorization: `Bearer ${access_token}`}     # only 30   
};




axios.get(repoUrl, null, config).then((responses) => {

    const repos = responses.data.map(({name, language, html_url, created_at, description}) => {
        return {name, language, html_url, created_at, description};
    })

    console.log("number of repo  ", repos.length);


}).catch(error => {
    console.log(`getrepos error: ${error}`)
});

by https://docs.github.com/en/rest/reference/repos#list-repositories-for-the-authenticated-user--parameters , there is a page parameter

but how should I write the for loop? should I loop the page with 1,2,3,4.... until server give me some error?

VonC · Accepted Answer · 2021-06-20 01:24:01Z

1

You can make a GraphQL query with Axios, as in this example, or in this article:

axios({
  url: 'https://graphql.com/graphql',
  method: 'post',
  data: {
    query: `
     query {
       viewer {
         repositories(isFork: false) {
           totalCount
         }
       }
    }`
  }
}).then((result) => {
  console.log(result.data)
});

Once you have the total number of repositories, you start looping (only the exact amount of loop), as described here:

  //Start fetching every page of repos.
  const fetchPromises = [], pageCount = Math.ceil(repoCount / 
    MAX_PER_PAGE);
  for (let pageI = 1; pageI <= pageCount; ++pageI) {
    const fetchPagePromise = fetch(baseUrl + '&page=' + pageI);
    fetchPromises.push(fetchPagePromise);
  }

answered Jun 20, 2021 at 1:24

VonC

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