Filter array with regex using Javascript

Question

I am not very well versed with coding. I have a set of strings in an array and I am trying to filter them out using regex but it's not working for me. I want my result array to return any string containing _number like _0, _01, _000

and the filter that I am using is

var myArray = ["bedroom_01", "bedroom_02", "bedroom" , "bathroom_01"];

var result = myArray.filter(name => name.includes("/_\d+/g"));

console.log(result);

The above code is returning me a blank array. Please let me know what am I doing wrong?

"/_\d+/g" -> /_\d+/g you're passing a string instead of a regex. EDIT: also you cannot use a regex in .inclues, you need to do regex.test(string). — VLAZ
– VLAZ, Commented Jun 1, 2021 at 12:27
That ain't a reg exp, that be a string and includes does not use a reg exp. — epascarello
– epascarello, Commented Jun 1, 2021 at 12:27
If my answer did not solve your problem please consider updating the question. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Nov 28, 2021 at 19:18

Wiktor Stribiżew · Accepted Answer · 2021-06-01 12:27:57Z

2

You need RegExp#test with a regex literal:

var myArray = ["bedroom_01", "bedroom_02", "bedroom" , "bathroom_01"];
console.log(
   myArray.filter(name => /_\d+/.test(name))
)

If you need to check if the array item ends with _ + digits, use /_\d+$/.

answered Jun 1, 2021 at 12:27

Wiktor Stribiżew

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Comments

zolamk · Accepted Answer · 2021-06-01 12:31:16Z

0

What you are passing to includes is a string not a regexp and includes takes a string not a regexp instead you can use the match method

var myArray = ["bedroom_01", "bedroom_02", "bedroom" , "bathroom_01"];

var result = myArray.filter(name => name.match(/_\d+/));

console.log(result);

answered Jun 1, 2021 at 12:31

zolamk

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