filter each array item with regex

Question

I have this regex that converts any # in a string to a hash tag array

myArr= myStr.match(/#\S+/g);

I also have a this to filter out from a string anything other than alpah numeric minus underscore.

myStr= myStr.replace(/[^a-zA-Z0-9_]/g, "");

But now i want to combine these 2 to make sure that each of the items in that array contain only alpha numeric values including underscore and the # in the begining.

Can anyone help out please, thank you.

You can't since it is two different operations.

Casimir et Hippolyte
– Casimir et Hippolyte

2013-12-14 21:14:05 +00:00
Commented Dec 14, 2013 at 21:14 — Casimir et Hippolyte
– Casimir et Hippolyte, Commented Dec 14, 2013 at 21:14

Niet the Dark Absol · Accepted Answer · 2013-12-14 21:31:46Z

1

Why so complicated?

myArr = myStr.match(/#[a-z0-9_]+/gi);

EDIT: I misunderstood your intention. Here's a slightly less simple, but altogether more efficient, solution:

myArr = myStr.replace(/#\S+/g,function(m) {
    return "#"+m.replace(/[^a-z0-9_]+/gi,"");
}).match(/#\S+/g);

edited Dec 14, 2013 at 21:31

answered Dec 14, 2013 at 21:12

Niet the Dark Absol

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9 Comments

Niet the Dark Absol Over a year ago

@NoahR Uh, no. It's intentional.

s_p Over a year ago

thank you, i took off the i. when i enter #hello_wor-ld expecting #hello_world, i get #h

Niet the Dark Absol Over a year ago

That's because I missed the +, sorry!

s_p Over a year ago

so i put the g back in and #hello_wor-ld produces ["#hello_wor"]

Noah R Over a year ago

@Niet the Dark Absol I was just testing you ;)

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