unexpected Http error ın api integration Flutter Http

Question

Hi there I am trying to integrate an api with flutter but a strange merged. Have an idea?

It shows link includes some '%' figure but especially it does not. Where is the problem. It is a basic think to post a request an api.

void yap ()async
  {
    //https://www.payfast.co.za/eng/process
    //https://sandbox.payfast.co.za/eng/process


    String url3 = "https://sandbox.payfast.co.za/eng/process";
    //String pkistring = v1hashing(requeststr);
    HttpClient httpClient = new HttpClient();
    HttpClientRequest request = await httpClient.postUrl(Uri.parse(url3));

    //headers
    //request.headers.set('Accept' ,  'application/json');
        Map body = { "merchant_id" :"10000100",
                    "merchant_key" :"46f0cd694581a",
                      "amount" :"100.00",
                          "item_name" :"Test Product"} ;
    
    //body
        request.add(utf8.encode(json.encode(body)));
    
    //response cevap
        HttpClientResponse response = await request.close();
        print(response.statusCode); // baglanti yapildi mi yapilmadi mi 200 ise yapildi
        String reply = await response.transform(utf8.decoder).join();
        //Map responseMap = json.decode(reply);
        httpClient.close();
        print("payfast ici odeme");
        print(reply);
    
      }

Error Text;

 Unhandled Exception: FormatException: sandbox.payfast.co%E2%80%8B is not a valid link-local address but contains %. Scope id should be used as part of link-local address. (at character 19)
sandbox.payfast.co%E2%80%8B
                  ^

How about changing Uri.parse(url3) into Uri.parse(url3.trim()). — cyberail
– cyberail, Commented May 29, 2021 at 22:14
Try adding 'r' to avoid special characters: String url3 = r"sandbox.payfast.co.za/eng/process"; — EyaS
– EyaS, Commented May 29, 2021 at 22:41
How about changing Uri.parse(url3) into Uri.parse(Uri.decodeFull(url)) — cyberail
– cyberail, Commented May 29, 2021 at 22:52
Yep. That you can define uri in different variavle for cleab code sake. — cyberail
– cyberail, Commented May 29, 2021 at 23:03

cyberail · Accepted Answer · 2021-05-29 23:16:05Z

2

Use Uri.https instead of Uri.parse.

In case if url is http use Uri.http.

But the structure of both methods are same. Docs for Uri.http: https://api.dart.dev/stable/2.10.5/dart-core/Uri/Uri.http.html

answered May 29, 2021 at 23:16

cyberail

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