I was wondering if it is possible to run an enumerate loop as as we can see below
int_term = [scipy.quad(t_x,x0,i)[0] for i in enumerate(x_vals)]
or do we have to write it this way
for i in enumerate(x_vals)
1 Answer
Hopefully this clarifies what exactly enumerate does:
>>> list(enumerate('abc'))
[(0, 'a'), (1, 'b'), (2, 'c')]
It just turns your list into a list of a pairs where each of your elements is joined with the index i.e. a with 0, b with 1 and c with 2.
That's not exactly true because it is an iterator rather than an actual list - so it provides you with values lazily when you wrap another iterator.
Looping over it is therefore the same as any other lists except usually it is done the following way:
for i, x in enumerate(xs)
You could still use:
for i in enumerate(xs)
but then just know that i is going to be a tuple with some int, and some object from xs.
enumerateisn't a loop at all. It's a iterable type that provides "annotated" elements from another iterable. You can iterate over it using whatever technique you would dive use to iterate over the original.quadexpects that theargsparameter be a tuple.ifrom enumerate will be tuple, but it might not be what yourt_xexpects. During testing, I suggest including a print at the start oft_xto display or otherwise tell you what the arguments are.