convert curl command to a Python request command

Question

I am trying to convert the following curl command to Python request command:

curl 'https://api.test.com/v1/data/?type=name&status=active' -H 'Authorization: apikey username:api_key_value'

I have tried a lot of possible solutions like the one below but nothing is working and I am getting a'401' code:

url = "https://api.test.com/v1/data/?type=name&status=active"
headers = {"content-type": "application/json", "Accept-Charset": "UTF-8"}
params = (
(username, api_key_value),
)
data = requests.get(url, headers=headers, params=params).json
print(data)

Tim Roberts · Accepted Answer · 2021-05-12 19:49:54Z

1

Params specifies the URL parameters. The Authorization thing is just another header. And response.json is a function.

url = "https://api.test.com/v1/data/"
headers = {
    "content-type": "application/json",
    "Accept-Charset": "UTF-8",
    "Authorization": "apikey {0}:{1}".format(username, api_key_value)
}
params = { 'type': 'name', 'status': 'active' }
data = requests.get(url, headers=headers, params=params).json()
print(data)

answered May 12, 2021 at 19:49

Tim Roberts

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1 Comment

chrysst Over a year ago

You Rock! Thank you so much for the answer and the explanation!! :)

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