Need recursive sql in oracle

I have a recursive query as below:

with addresses as

(

  select cust_id,address addr from

  (

  select 10 cust_id,'9 Help Street, Level 4' address from dual union all

  select 11 cust_id,'22 Victoria Street' address from dual union all

  select 12 cust_id,'1495 Franklin Str.' address from dual union all

  select 13 cust_id,'30 Hasivim St.,Petah-Tikva' address from dual union all

  select 14 cust_id,'2 Jakaranda St' address from dual union all

  select 15 cust_id,'61, Science Park Rd' address from dual union all

  select 16 cust_id,'61, Social park road.' address from dual union all

  select 17 cust_id,'Av. Hermanos Escobar 5756' address from dual union all

  select 18 cust_id,'Ave. Hermanos Escobar 5756' address from dual union all

  select 19 cust_id,'8000 W FLORISSANT Ave.' address from dual union all

  select 20 cust_id,'8600 MEMORIAL PKWY SW' address from dual union all

  select 21 cust_id,'8200 FLORISSANTMEMORIALWAYABOVE SW' address from dual union all

  select 22 cust_id,'8600 MEMORIALFLORISSANT PKWY SW.' address from dual

  ) t1

),

 replacements as

  (

  select id,to_str,from_string from_str from

  (

  select 1 id,'St' to_str,'Street' from_string from dual union all

 select 2 id,'St' to_str,'St' from_string from dual union all

 select 3 id,'St' to_str,'Strit' from_string from dual union all

 select 4 id,'St' to_str,'Str' from_string from dual union all

 select 5 id,'Rd' to_str,'Rd.' from_string from dual union all

 select 6 id,'Rd' to_str,'road' from_string from dual union all

 select 7 id,'Av' to_str,'Av.' from_string from dual union all

 select 8 id,'Av' to_str,'Ave' from_string from dual union all

 select 9 id,'Av' to_str,'Avenue' from_string from dual union all

 select 10 id,'Av' to_str,'Aven.' from_string from dual union all

 select 11 id,'West' to_str,'W' from_string from dual union all

 select 12 id,'South West' to_str,'SW' from_string from dual

 ) t2

),

 r(cust_id,addr,test_addr,l) as 

 (

   select cust_id,addr,regexp_replace(addr,'(^|\W)' || from_str || '(\W|$)','\1' || to_str || '\2') test_addr,

     id - 1

     from  

     addresses,

     replacements

     where id = (select count(*) from replacements)

   union all

     select cust_id,addr,regexp_replace(test_addr,'(^|\W)' || from_str || '(\W|$)','\1' || to_str || '\2') test_addr,

     l - 1

     from r,

     replacements

     where id = l

  )

 select cust_id,addr,test_addr,l

 from r

 where l=0

 ;

present output:

Query not working as expected for cust_id like 16,18,22. in cust_id dot is there after road but still it changes to Rd.

I need 2 queries...one with exact match including dot and the other sql having match with dot or without dot.

The expect out put for first sql with exact match:

The expected output with second sql with or without dot:

Thanks

Thanks,