Compare user input with a list in Python

You can add something like this:

word = input("Enter a word : ")
try:
    word = int(word)
except ValueError:
    print("Values is not int")

• Avoid using list as a variable name
• Use string data in your list
• Use in to check element presence in your list

Code:

lst = ['test', 'testOne', '5', '10']
word = input('Enter a word : ')
if word in lst:
    print('OK')
else:
    print('Not OK')

To check user input value for each of the elements from a list containing both String and Integer type data, we can use a try-except block.

• At first, we will check if the user input and list item contain integer data in a try block. If the data matches, we will print Ok to the user.
• If the above try block throws an exception, we will verify if both values are matched. If the data matches, we will print Ok to the user.

If none of the above cases are affirmative for all the items on the list, we will print Not ok to the user.

data = ["test", "testOne", 5, 10]

while True:
      word = input("Enter a word : ")
      if word == "exit":
            break
      word_found = False
      for element in data:
            try:
                  if int(word) == int(element):
                        word_found = True
                        break
            except ValueError:
                  if word == element:
                        word_found = True
                        break
      if word_found:
            print("Ok")
      else:
            print("Not ok")

Output:

Enter a word : Shovon
Not ok
Enter a word : test
Ok
Enter a word : 34
Not ok
Enter a word : 5
Ok
Enter a word : Ahmedur
Not ok
Enter a word : testOne
Ok
Enter a word : exit

1. You don't need to iterate through the list using for loop as you can check existence of an element using "in" operator So

    if word in list:
         print("OK")

is sufficient.

2. If you want to ensure only integer is entered, just validate the user input like int(word)

Thanks for your answer guys ! I tried it in another way

list = ["test", "testOne", 5, 10]
continuer = True


def safe_cast(val, to_type, default=None):
    try:
        return to_type(val)
    except (ValueError, TypeError):
        return default

while continuer:
    word = input("Enter a word : ")
    for element in list:
        if isinstance(element, str) and element == word:
            print("Ok")
            break
        elif isinstance(element, int) and safe_cast(word, int, 0) == element:
            print("ok")
            break

And it worked well ! Sorry for the inconvenience

You can try this

    list = ["test", "testOne", 5, 10]
    continuer = True
    getlist1=str(list)  #Converting all the elements in list to string
    while continuer:
        word = input("Enter a word : ")            
        for elements in list:
            if ((word) in (getlist1)):
                print("Ok")
                break
            else:
                print("Not ok")
                break

Output: Enter a word : 5

Ok

Enter a word : 10

Ok

Enter a word : test

Ok

Enter a word : testOne

Ok

Enter a word : hello

Not ok