#Basically, for the input number given, return results that are smaller
#than it compared with the list.
n = list(input('Please enter a Number: '))
#map(int, str(n))
newlist = []
a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
for n in a:
if n > a:
newlist.append(a)
print(newlist)
Not asking for the solution but just asking how n can work as a list since when I run my code, it says:
" if n > a:
TypeError: '>' not supported between instances of 'int' and 'list' "
Here is what you need. You can use a list comprehension to filter a for required elements.
x = int(input('Please enter a Number: '))
# Input 5 as an example
a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
result = [i for i in a if i < x]
print(result)
# [1, 1, 2, 3]
n is a list from a string input. On the other, for n in a is using n to iterate elements of a. Sometimes providing another method enlightens the OP.n int is more local than n listAssuming you're using python3, the input() method returns a string.
So if your user inputs the value 42, input() will return "42", (type 'str').
Then you are converting your string into a list, so going on with the 42 example, you'll have list("42") == ["4", "2"], and you store this list in n.
Anyway, you're not using your variable n anymore:
The for loop that you wrote does not not refer to the n variable you previously created (see namespaces), but creates a new variable which will contain each number in your a list.
this means that you are comparing each number of the list to the whole list:
1 > [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
1 > [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
2 > [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
3 > [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
...
In python3 this will raise a TypeError, and in python2 the behaviour won't be what you expect.
To have your code correctly working, you may take the user input and convert it in an integer, then compare this integer with each number inside your list and append the number to a new list if it is lower than the input integer:
myint = int(input('Please enter a Number: '))
# type(myint) == int
newlist = []
a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
# for each (n)umber in list (a):
for n in a:
# if the provided number is higher than the actual number in list (a):
if myint > n:
newlist.append(n)
# print the new list once its fully filled
print(newlist)
because a is a list and your n in the iteration is an integer value inside of the list a. for example in the zeroth iteration n = 1 but a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89] and saying n > a doesn't make sense, does it?
