How to check if array inside object is empty JavaScript

Question

const isEmpty = Object.keys(data).every((key) => {
  return data[key].length === 0;
});

How can I check if all arrays in objects are empty. Problem with this code I tried is that I get this:

data {
    0: Array[]
    1: Array[]
    2: Array[]
}
data {
    0: Array[]
    1: Array[1]
    2: Array[]
}

For first object I get false and that's okay but for the second I get true but I want to get false until all of arrays.length > 0, so I need to get true only for this situation:

obj {
    0: Array[1]
    1: Array[1]
    2: Array[1]
}

If you know that you want the following arrays.length > 0. Then why don't you use it instead of length === 0? — StackByMe
– StackByMe, Commented Feb 9, 2021 at 8:26
your data is completely invalid. What should Array[0] be? If that is really your code, that will not return false or true but just throw errors ... — derpirscher
– derpirscher, Commented Feb 9, 2021 at 8:27
What do you mean by writing Array[0] etc.? if you mean an array with 0 elements then your solution will give true for the first and false for the second, not false for the first and true for the second. Also, your desired result is unclear, you say you want it to be true until all of arrays.length > 0, but then say "I need to get true only for this situation", which suggests you want true only when all arrays.length's equal 1 — Nick Parsons
– Nick Parsons, Commented Feb 9, 2021 at 8:27

Nina Scholz · Accepted Answer · 2021-02-09 08:26:18Z

5

You could check the lenght of all values.

const isEmpty = data => !Object.values(data).every(({ length }) => length);

console.log(isEmpty({ 0: [], 1: [], 2: [] }));
console.log(isEmpty({ 0: [], 1: [1], 2: [] }));
console.log(isEmpty({ 0: [0], 1: [1], 2: [2] }));

answered Feb 9, 2021 at 8:26

Nina Scholz

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3 Comments

Jasmijn Over a year ago

I think const isEmpty = data => Object.values(data).every(({ length }) => !length); otherwise the function should be named someEmpty or something like that.

Nina Scholz Over a year ago

naming is up to op. i would prefer hasEmptyArrays ...

Jasmijn Over a year ago

Ah, you're right. I missed the fact that the desired behaviour doesn't match the name OP has given the function.

samuelcolt · Accepted Answer · 2021-02-09 08:38:16Z

1

Use Object.values method.

Object.values(data).some(it => !it.length)

edited Feb 9, 2021 at 8:38

answered Feb 9, 2021 at 8:25

samuelcolt

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2 Comments

Rajesh Dixit Over a year ago

This will not work but you are close enough

samuelcolt Over a year ago

@Rajesh sorry i forgot ! operator before it.length

Vince · Accepted Answer · 2021-02-09 08:36:19Z

0

The solution

function CheckArray(obj) {
  this.haveItems = false;

  this.onCheck = function (obj) {
    let createdArr = Object.values(obj);
    
    for (let i = 0; i < createdArr.length; i++) {
      if (createdArr[i].length > 0) {
        this.haveItems = true;
        break;
      }
    }
  };
}

let data = {
  0: [],
  1: [],
  2: [],
};

let a = new CheckArray();
a.onCheck(data);

console.log(a);

answered Feb 9, 2021 at 8:36

Vince

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