Javascript check if all values in an object array are empty

Question

I have an array like below.

let report = [
  {0: { error1: '', error2: ''}},
  {1: { error1: '', error2: ''}}
]

I want to check if all the error values are empty. Then based on that result I will enable or disable a button. If all the error values are empty, then the save button will be enabled. How can I achieve that ?

What have you tried so far?

Rohit Kashyap
– Rohit Kashyap

2021-01-27 10:57:47 +00:00
Commented Jan 27, 2021 at 10:57 — Rohit Kashyap
– Rohit Kashyap, Commented Jan 27, 2021 at 10:57
Check it's syntax report, haven't found anything useful.

Rahul
– Rahul

2021-01-27 11:00:37 +00:00
Commented Jan 27, 2021 at 11:00 — Rahul
– Rahul, Commented Jan 27, 2021 at 11:00

Taghi Khavari · Accepted Answer · 2021-01-27 11:04:08Z

1

See this:

let report = [
  { 0: { error1: "", error2: "" } },
  { 1: { error1: "", error2: "" } },
];

const testToSeeAllErrorsAreEmpty = report.every((item) =>
  Object.values(item).every((objContainsErrors) =>
    Object.values(objContainsErrors).every((error) => !error)
  )
);

console.log("testToSeeAllErrorsAreEmpty: ", testToSeeAllErrorsAreEmpty)

answered Jan 27, 2021 at 11:04

Taghi Khavari

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Comments

Ori Drori · Accepted Answer · 2021-01-27 12:26:44Z

This recursive function checks if an object (or array) is empty, if not iterates it's properties, and check if they are empty. If the a property is an object (or array), the function checks if it's empty and so on. Only if all leaves are empty, the function returns true.

const checkEmptyLeaves = o => {
  if(_.isObject(o)) return _.isEmpty(o) || _.every(o, checkEmptyLeaves);
  
  return _.isEmpty(o);
};

const report1 = [
  { 0: { error1: "", error2: "" } },
  { 1: { error1: "", error2: "" } },
];

const report2 = [
  { 0: { error1: "", error2: { message: "some message" } } },
  { 1: { error1: "", error2: "" } },
];

console.log(checkEmptyLeaves(report1));
console.log(checkEmptyLeaves(report2));

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