I am trying to extract version from below mentioned URL's using shell commands like, grep, awk, sed, cut which ever is most suitable
https://abcd/efgh/1.1.3/hijkl/mnop
https://abcd/efgh/hijkl/2.3.4.5/mnop
https://abcd/3.4/efgh/hijkl/mnop
I am looking to extract the version(numbers with dot) alone from the URL, where the position may vary as in above example. Looking for suggestions.
Expected output to be :
1.1.3
2.3.4.5
3.4
You may use this grep:
grep -Eo '[0-9]+(\.[0-9]+)+' file
1.1.3
2.3.4.5
3.4
With awk, written and tested with shown samples in GNU awk.
awk 'match($0,/([0-9]+\.){1,}[0-9]+/){print substr($0,RSTART,RLENGTH)}' Input_file
Explanation: Adding detailed explanation for above.
awk ' ##Starting awk program from here.
match($0,/([0-9]+\.){1,}[0-9]+/){ ##using match function to match regex of ([0-9]+\.){1,}[0-9]+ in current line.
print substr($0,RSTART,RLENGTH) ##Printing sub string of matched regex above, starting index is RSTART till value of RLENGTH here.
}
' Input_file ##Mentioning Input_file name here.
I would use GNU AWK following way, let file.txt content be
https://abcd/efgh/1.1.3/hijkl/mnop
https://abcd/efgh/hijkl/2.3.4.5/mnop
https://abcd/3.4/efgh/hijkl/mnop
then
awk 'BEGIN{RS="[/\n]"}/^[.[:digit:]]+$/' file.txt
output
1.1.3
2.3.4.5
3.4
Explanation: I specify row seperator (RS) as either / or newline (\n) then print only rows (i.e. parts between / or newline and / or / and newline) which contain only . or digits - in order to achieve such effect I use ^ and $ denoting start and end of record.
