Why doesn't exit() stop the script after the first iteration?
In my opinion, it has to stop after the first iteration.
>>> def func(q):
... def funct(y):
... try:
... print(y)
... exit()
... except:
... pass
... funct(q)
...
>>> a=['1','2','3','4','5','6','7']
>>> for x in a:
... func(x)
...
1
2
3
4
5
6
7
>>>
To answer your question as directly as possible,
Why doesn't
exit()stop the script after the first iteration?
Because a bare except will catch BaseException and Exception, and since exit() raises a SystemExit, which is a BaseException subclass, your code will swallow the exception and pass on each iteration.
Note the difference if you catch Exception only, which does not suppress a BaseException:
>>> from sys import exit
>>>
>>> def func(q):
... def funct(y):
... try:
... print(y)
... exit()
... except Exception:
... pass
... funct(q)
...
>>> a = ['1','2','3','4','5','6','7']
>>> for x in a: func(x)
...
1 # exits
try: sys.exit(0) and move it to the scope of the global function
import sys
def func(q):
def funct(y):
try:
print(y)
except:
pass
funct(q)
sys.exit(0)
a=['1','2','3','4','5','6','7']
for x in a:
func(x)
Output: 1
exceptdo nothing and script go on. Thanks.