How to create an ARRAY in PHP to display correct format?

Question

I am in a unique fix. It is easy but for the love of god I havent able to figure it out.

Code

// Loop through results
for($k=0;$k<count($orderNumber);$k++) {
    // Add a new array for each iteration
    $div[] = array (
        $orderNumber[$k]=>array(
            "customerOrderId"=>$orderNumber[$k],
            "status"=>$orderStatus[$k],
            "readyTime"=>$orderShipDate[$k]
        ));
}

Returns

[
  {}
  {}
  {}
]

I although need the API to return in the following format.

"orders" : {
  {}
  {}
  {}
}

Can someone guide me in the correct direction?

Add a key named orders, like $div['orders'] = array (...). And you can't have an object of objects like you want, you will have "orders": [ {}, {}, {} ] as final result. — Felippe Duarte
– Felippe Duarte, Commented Oct 26, 2020 at 19:17

Progrock · Accepted Answer · 2020-10-26 23:43:49Z

1

<?php
$orderNumber   = ['10', '23'];
$orderStatus   = ['pending', 'shipped'];
$orderShipDate = ['2023', '2019'];

for($k=0;$k<count($orderNumber);$k++) {
    $div['orders'][$orderNumber[$k]] = array (
            "customerOrderId"=>$orderNumber[$k],
            "status"=>$orderStatus[$k],
            "readyTime"=>$orderShipDate[$k]
    );
}

echo json_encode($div, JSON_PRETTY_PRINT);

Output:

{
    "orders": {
        "10": {
            "customerOrderId": "10",
            "status": "pending",
            "readyTime": "2023"
        },
        "23": {
            "customerOrderId": "23",
            "status": "shipped",
            "readyTime": "2019"
        }
    }
}

If you drop the order keying for a sequential append you'll get a list output:

$div['orders'][] = array (

Output (with the line above swapped in):

{
    "orders": [
        {
            "customerOrderId": "10",
            "status": "pending",
            "readyTime": "2023"
        },
        {
            "customerOrderId": "23",
            "status": "shipped",
            "readyTime": "2019"
        }
    ]
}

answered Oct 26, 2020 at 23:43

Progrock

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1 Comment

Parth Kadakia Over a year ago

Thank you so much. I was almost close.

Parth Kadakia · Accepted Answer · 2020-10-29 13:47:21Z

0

Thank you to all of you who helped me. This is what I ended up with and works perfectly as I need.

for($k=0;$k<count($orderNumber);$k++) {
        // Add a new array for each iteration
        $div['orders'][$orderNumber[$k]] = array (
            "customerOrderId"=>$orderNumber[$k],
            "status"=>$orderStatus[$k],
            "readyTime"=>$orderShipDate[$k]);
}

answered Oct 29, 2020 at 13:47

Parth Kadakia

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