Passing a Bash shell variable into AppleScript file

Question

I am currently learning how to use bash shell scripting with AppleScript. I have a problem. The problem is how to pass a bash variable into an osascript The example is as following:

read input
foo $input

foo(){
    osascript path/to/script.scpt $1
}

my question is how to convert input into something that would be accepted by the script.scpt since $1 would not be recognized by the script.scpt . Thanks

notthetup · Accepted Answer · 2020-09-09 05:17:19Z

1

Actually that should work since bash will automatically set the value of $1 to be the argument you passed to foo. So in this scenario, it would be the input that you read.

I cleaned up you bash script a little..

#!/bin/bash

foo(){
  echo "Calling Apple script with argument $1"
  osascript script.scpt "$1"
}

read input
foo "$input"

And with this AppleScript,

on run argv
  return "hello, " & item 1 of argv & "."
end run

I get this output..

> ./test.sh
crazy world
Calling Apple script with argument world
hello, crazy world.

edited Sep 9, 2020 at 5:17

answered Sep 9, 2020 at 4:35

notthetup

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4 Comments

newbie Over a year ago

what if the value of $1 is a string with spaces? I used the run handler to split the string but it does not work. For example, the value of $1 is "About This Mac,Apple" . I changed the delimiter from space to "," so that it should be parsed to "About This Mac" and "Apple", which are the two items of argv that I need. But it does not seem to work

notthetup Over a year ago

Ah yes. That can be solved with a few quotes.. I will update the answer above.

notthetup Over a year ago

This is a great read to avoid common gotcas in bash mywiki.wooledge.org/BashPitfalls

newbie Over a year ago

Thanks so much !

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