Sort a list in java into a specific order

You can try something like this

        List<String> strings = Arrays.asList("OBJECTIVE", "ENERGY_POLICY", "TRAINING", "ENERGY_PERFORMANCE", "INTERNAL_AUDIT_REVIEW",  "LEGAL_REQUIREMENTS_REVIEW", "TASKS_REVIEW, SEU_REPORT", "CORRECTIVE_ACTIONS", "INTERNAL_AND_EXTERNAL_PARTIES");

        Map<String, Integer> ranks = new HashMap<>();

        // Assign rank to each element and store in ranks map. This map will be used for retrieving rank of each element while defining custom sorter
        for (int i =0 ; i< strings.size() ; i++) {
            ranks.put(strings.get(i),i);
        }

        // Now lets take a list which needs to sorted based on above order
        List<String> stringsToBeSorted  = Arrays.asList("ENERGY_POLICY", "OBJECTIVE", "TRAINING", "SEU_REPORT", "ENERGY_PERFORMANCE", "INTERNAL_AND_EXTERNAL_PARTIES", "INTERNAL_AUDIT_REVIEW", "LEGAL_REQUIREMENTS_REVIEW", "TASKS_REVIEW", "CORRECTIVE_ACTIONS");

        stringsToBeSorted.sort(new Comparator<String>() {
            @Override
            public int compare(String str1, String str2) {
                if (ranks.get(str1) == null || ranks.get(str2) == null) {
                    return 0;
                }

                return ranks.get(str1) - ranks.get(str2);
            }
        });

Or with Java 8

        stringsToBeSorted.sort(Comparator.comparingInt(ranks::get));  

But you need to make sure that strings has all the values and there should be no value in stringsToBeSorted list which is not present in strings list. as it will throw null pointer exception as its rank retrieved from hashmap is null

You can put each constant in a hash map with the constant as key and the position as the value.

now as and when you receive the constants get the position it should be from the hashmap and based on it create the final list