PHP: Trying to access array offset on value of type null

Question

Here is the line that the error is coming from...

If (password_verify($password, $user['password'])){}

Here is what's inside this of statement...

    $_SESSION['id'] = $user['id']; 
    $_SESSION['username'] = $user['username']; 
    $_SESSION['email'] = $user['email']; 
    $_SESSION['verified'] = $user['verified']; 
    $_SESSION['message'] = "Success!"; 
    $_SESSION['alert-class'] = "alert-success"; 
    header ('location: verification.php'); 
    exit(); 
} else { 
    $errors['login_fail'] = "Incorrect Username or Password"; 
}

The error occurs whenever i attempt to enter both a username and password combination that does not exist in the database. — Ryan Lewis
– Ryan Lewis, Commented Apr 28, 2020 at 20:37
I assume you did $user = some_fetch(); or something which is returning null because no rows in DB. Show more code. — AbraCadaver
– AbraCadaver, Commented Apr 28, 2020 at 20:43
And what's your question? What have you tried to debug this problem? — Nico Haase
– Nico Haase, Commented Apr 28, 2020 at 20:57

Michal Hynčica · Accepted Answer · 2020-04-28 20:47:17Z

1

You need to check if you've managed to load the user from DB. It looks like the function that is loading data from DB returns null when the user is not found.

You can change your condition to something like this:

if(!empty($user) && password_verify($password, $user['password'])) {
  // ... log in user
} else {
  // ... do something when password or user doesn't match
}

answered Apr 28, 2020 at 20:47

Michal Hynčica

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1 Comment

Ryan Lewis Over a year ago

I apologize, first time using this platform.

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