Java stream - map and store array of int into Set

Question

I have an array of [5, 6, 7, 3, 9], I would like to change each element from the array substracting by 2, then store the in a Set, so what I did is

Set<Integer> mySet = Arrays.stream(arr1).map(ele -> new Integer(ele - 2)).collect(Collectors.toSet());

but I am getting two exceptions here as

The method collect(Supplier<R>, ObjIntConsumer<R>, BiConsumer<R,R>) in the type IntStream is not applicable for the arguments (Collector<Object,?,Set<Object>>)"
Type mismatch: cannot convert from Collector<Object,capture#1-of ?,Set<Object>> to Supplier<R>

What does those error mean and how can I fix the issue here with Java Stream operation?

Dont use new Integer(...), it is deprecated for good reason. Use Integer.valueOf(...) instead. — Zabuzard
– Zabuzard, Commented Apr 27, 2020 at 6:16
Closely related if not duplicate - How do I convert a Java 8 IntStream to a List? — Naman
– Naman, Commented Apr 27, 2020 at 6:25
@Naman Very closely related, but I am not sure if it is a duplicate, because OP doesn't seem to have known that they were working with an IntStream — Lino
– Lino, Commented Apr 27, 2020 at 6:30
@Lino at least the error message reads that explicitly, just some debugging efforts away if I could say so. — Naman
– Naman, Commented Apr 27, 2020 at 6:39

Eran · Accepted Answer · 2020-04-27 06:14:19Z

12

It looks like arr1 is an int[] and therefore, Arrays.stream(arr1) returns an IntStream. You can't apply .collect(Collectors.toSet()) on an IntStream.

You can box it to a Stream<Integer>:

Set<Integer> mySet = Arrays.stream(arr1)
                           .boxed()
                           .map(ele -> ele - 2)
                           .collect(Collectors.toSet());

or even simpler:

Set<Integer> mySet = Arrays.stream(arr1)
                           .mapToObj(ele -> ele - 2)
                           .collect(Collectors.toSet());

answered Apr 27, 2020 at 6:14

Eran

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2 Comments

Drex Over a year ago

yes, you're right, the arr1 is an int[], so does it mean .boxed().map(ele -> ele - 2) and .mapToObj(ele -> ele - 2) both returns an IntStream? and is boxed() only could be applied on IntStream to convert into an Stream<Integer>?

Eran Over a year ago

No, they both return a Stream<Integer>. They are applied on IntStream. And yes, boxed() converts an IntStream to a Stream<Integer>.

ernest_k · Accepted Answer · 2020-04-27 06:14:55Z

7

Arrays.stream(int[]) returns an IntStream. And IntStream does not offer collect() methods that take a Collector.

If you need to use Collectors.toSet(), then you need a Stream<Integer> for it, and you can call mapToObj for that:

Set<Integer> mySet = Arrays.stream(arr1)
                           .mapToObj(ele -> ele - 2)
                           .collect(Collectors.toSet());

answered Apr 27, 2020 at 6:14

ernest_k

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Comments

Donald Raab · Accepted Answer · 2020-05-16 04:11:30Z

0

If you're open to using a third-party library, you can avoid boxing the int values as Integer using Eclipse Collections IntSet.

int[] array = {5, 6, 7, 3, 9};
IntStream stream = Arrays.stream(array).map(value -> value - 2);
IntSet actual = IntSets.mutable.ofAll(stream);
IntSet expected = IntSets.mutable.of(3, 4, 5, 1, 7);
Assert.assertEquals(expected, actual);

Note: I am a committer for Eclipse Collections.

answered May 16, 2020 at 4:11

Donald Raab

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