async functions in Javascript

Question

I have below function inside an async function.

await saveStock(stock).then((res) => {
 addDrugToStock(stockDrug)
  addSupplierToStock(stockSupplier)

});

When I run this it always saveStock function gives appropriate results. but the other two functions are not executing properly. Sometimes addDrugToStock is working. In other times adSupplierToStock is working. How can I run both addDrugToStock and addSupplierToStock at a same time.

How can I **run** both... at a same time. You cannot run but you can get the values at the same time — Tân
– Tân, Commented Apr 17, 2020 at 19:21
Use Promise.all for parallel function call stackoverflow.com/questions/35612428/… — user13342477
– user13342477, Commented Apr 17, 2020 at 19:32

Danil Sabirov · Accepted Answer · 2020-04-17 19:36:02Z

1

If you want to execute both Promise objects and wait for both of them, then you need to use Promise.all: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise/all

answered Apr 17, 2020 at 19:36

Danil Sabirov

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user13278024 · Accepted Answer · 2020-04-17 19:37:34Z

1

When using async/await operators you don't have to implement the .then() or .catch() handlers, just write code the synchronous way. Otherwise, you can use Promise.all to handle multiple independent Promises.

try {
   // Equal to .then() in regular Promises

   const response = await saveStock(stock);

   addDrugToStock(stockDrug);
   addSupplierToStock(stockSupplier);
} catch (e) {
   // Equal to .catch() in regular Promises
}

answered Apr 17, 2020 at 19:37

user13278024

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