Bash Scripting - Exiting While Loop When User Input = "done"

Question

How do you exit a while loop in bash when user input detects "done"?

The objective is to have users input restaurant names and when they type done, the while loop escapes and and it randomly spits out a random restaurant within the array? As of right now, it only escapes when CTRL + D but this also closes the terminal

P.S: I've only been playing with bash for about 2 hours!

echo 'Where are you having trouble deciding? Type done to finish'

while read restaurants
do
  rest_array=("${rest_array[@]}" $restaurants)
done


echo Eat at ${rest_array[$rand]}

rest_array+=("$restaurants") is a simpler way to append to the array. — chepner
– chepner, Commented Feb 14, 2020 at 16:31

Francesco Gasparetto · Accepted Answer · 2020-02-14 16:38:59Z

1

Use break to exit the loop in bash

echo 'Where are you having trouble deciding? Type done to finish'

while read restaurants
do
  if [[ "$restaurants" == "done" ]]; then
     break
  fi
  rest_array+=("$restaurants")
done


echo Eat at ${rest_array[$rand]}

edited Feb 14, 2020 at 16:38

answered Feb 14, 2020 at 16:28

Francesco Gasparetto

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9 Comments

Wandering Coffee Bean Over a year ago

I tried this way but it closes out of the script completely (using WIN10)

Francesco Gasparetto Over a year ago

What kind of shell are you using?

Wandering Coffee Bean Over a year ago

Using bash, file name randomrest.sh

Francesco Gasparetto Over a year ago

It's strange. Can you explain "it closes out of the script completely" please?

Wandering Coffee Bean Over a year ago

Sure. When I open the script (double clicking the script file), I input relevant texts, and once I type done then enter, the bash window just closes as if I type CTRL + D or X out the window. I hope I'm describing it properly

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